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kari74 [83]
3 years ago
6

X=y7+10y= First one gets a crown!

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
5 0

Answer:

y^7+10y=x it all goes both ways when you try solving for x and y

Step-by-step explanation:

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\\ \rm\Rrightarrow \left(x+\dfrac{1}{x}\right)^2

\\ \rm\Rrightarrow \left(\dfrac{x^2+1}{x}\right)^2\dots(1)

  • .Find x²

\\ \rm\Rrightarrow \left(\dfrac{1}{\sqrt{2}+\sqrt{5}}\right)^2

\\ \rm\Rrightarrow \dfrac{1}{2+2\sqrt{10}+5}

\\ \rm\Rrightarrow \dfrac{1}{2\sqrt{10}+7}

Now put in eq(1)

\\ \rm\Rrightarrow \left(\dfrac{\dfrac{1}{2\sqrt{10}+7}+1}{\dfrac{1}{2\sqrt{10}+7}}\right)^2

\\ \rm\Rrightarrow \left(\dfrac{1+2\sqrt{10}+7}{2\sqrt{10}+7}\times (2\sqrt{10}+7)\right)^2

\\ \rm\Rrightarrow \left(\dfrac{2\sqrt{10}+8}{2\sqrt{10}+7}\times (2\sqrt{10}+7)\right)^2

\\ \rm\Rrightarrow \left(\dfrac{(2\sqrt{10}+8)\cancel{(2\sqrt{10}+7)}}{\cancel{2\sqrt{10}+7}}\right)^2

\\ \rm\Rrightarrow (2\sqrt{10}+8)^2

\\ \rm\Rrightarrow 40+32\sqrt{10}+64

\\ \rm\Rrightarrow 32\sqrt{10}+94

More simplification (If required)

\\ \rm\Rrightarrow 2^52^{\frac{1}{2}}\sqrt{5}+94

\\ \rm\Rrightarrow 2^{5+\frac{1}{2}}\sqrt{5}+94

\\ \rm\Rrightarrow 2^{\frac{11}{2}}\sqrt{5}+94

\\ \rm\Rrightarrow \sqrt{2^{11}}\sqrt{5}+94

\\ \rm\Rrightarrow \sqrt{2048(5)}+94

\\ \rm\Rrightarrow \sqrt{10240}+94

Most accurate

\\ \rm\Rrightarrow 101.19+94

\\ \rm\Rrightarrow 195.19

6 0
3 years ago
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