Part a.
The domain is the set of x values such that 
, basically x can be equal to -1/2 or it can be larger than -1/2. To get this answer, you solve 
for x (subtract 1 from both sides; then divide both sides by 2). I set 2x+1 larger or equal to 0 because we want to avoid the stuff under the square root to be negative.
If you want the domain in interval notation, then it would be 
which means the interval starts at -1/2 (including -1/2) and then it stops at infinity. So technically it never stops and goes on forever to the right.
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Part b.
I'm going to use "sqrt" as shorthand for "square root"
f(x) = sqrt(2x+1)
f(10) = sqrt(2*10+1) ... every x replaced by 10
f(10) = sqrt(20+1)
f(10) = sqrt(21)
f(10) = 4.58257569 which is approximate
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Part c.
f(x) = sqrt(2x+1)
f(x) = sqrt(2(x)+1)
f(x+2a) = sqrt(2(x+2a)+1) ... every x replaced by (x+2a)
f(x+2a) = sqrt(2x+4a+1) .... distribute
we can't simplify any further
Answer:
37.50 and 84.97
Step-by-step explanation:
Answer: The numbers are 1 and 3.
Step-by-step explanation:
Let x = smaller number , y= larger number.
As per given,
...(i)
...(ii)
Put value of x from (i) in (ii)
Since numbers are positive , so y=3 is correct.
And x will be 1 [from (i)]
Hence, the numbers are 1 and 3.
Since the toss can either be heads or tails and only one of these can land at a time the answer is 13
We have that
x²<span>-20x
</span><span>Group
terms that contain the same variable
</span>(x²-20x)
Complete
the square
(x²-20x+10²)------> (x-10)²
the answer is
the number must be 100
