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nika2105 [10]
3 years ago
6

Solve and type in a different form by using the given theorems of logarithms

Mathematics
1 answer:
scoray [572]3 years ago
4 0

\log\left(\frac{10}{y}\right) = \log(10) - \log(y)

The general rule is

\log\left(\frac{A}{B}\right) = \log(A) - \log(B)

Other log rules are

\log(AB) = \log(A) + \log(B)

B\log(A) = \log(A^B)

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Y∝√x If y=60 when x=36 find,y when x=16
avanturin [10]

Answer:

y = 10√16) = 40

Step-by-step explanation:

This says, "y is proportional to the square root of x."  We are told that y = 60 when x = 36.  Find the formula for this function.  Then, determine what value y will take on when x = 16.

y = k√x  becomes 60 = k√36, or 60 = 6k.  Then k must be 10, and the formula is y = 10√x.

If x = 16, y = 10√16) = 40

7 0
2 years ago
Stuffed animals each weighing 1/4 pound are on a scale. The scale shows 1 1/2 pounds. How many stuffed animals are on the scale?
Nady [450]
Here you go brodie .....

7 0
2 years ago
Solve the equation.<br><br> 3(k−6)=15
Natali [406]

Answer:

K = 11

Step-by-step explanation:

3(k - 6) = 15

3k - 18 = 15

3k = 15 + 18

3k = 33

K = 33/3

K = 11

Thus, the value of K is 11

8 0
2 years ago
PLEASE HELP ME EVERYONE HAS GOTTEN THIS WRONG ITS GONNA SUBMIT IN 15 MIN PLS HELP THANK YOU
LiRa [457]

Answer:

x=4.8

This here you use Pythagorean Theorem.

Step-by-step explanation:

a^2+b^2=c^2

The longest side is c. And the two legs are a and b.

So it'd be 11^2+x^2=12^2

121+x^2=144

Subtract 121 from both sides.

x^2=23

Then take the √ of x^2 and 23

So √x^2=√23

x=4.8

Hope this helps

5 0
3 years ago
Triangle ABC and Triangle DEF are similar. For triangle ABC, AB = 2x , AC = 24 inches and BC = 20. For triangle DEF, EF = 5 and
Norma-Jean [14]
X=8.

Following the similarity statement, we know that AC is to DF as BC is to EF.  The ratio would be:

24/(x-2) = 20/5

Cross multiply:
24*5 = 20(x-2)

Use the distributive property:
120 = 20x - 40

Add 40 to both sides:
120+40 = 20x - 40 + 40
160 = 20x

Divide both sides by 20:
160/20 = 20x/20
8 = x
8 0
3 years ago
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