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nika2105 [10]
3 years ago
6

Solve and type in a different form by using the given theorems of logarithms

Mathematics
1 answer:
scoray [572]3 years ago
4 0

\log\left(\frac{10}{y}\right) = \log(10) - \log(y)

The general rule is

\log\left(\frac{A}{B}\right) = \log(A) - \log(B)

Other log rules are

\log(AB) = \log(A) + \log(B)

B\log(A) = \log(A^B)

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The graph shows the feasible region for the system with constraints:
Dimas [21]

Answer:

The vertices feasible region are (0 , 15) , (10 , 15) , (20 , 5)

The minimum value of the objective function C is 125

Step-by-step explanation:

* Lets look to the graph to answer the question

- There are 3 inequalities

# y ≤ 15 represented by horizontal line (purple line) and cut the

  y-axis at point (0 , 15)

# x + y ≤ 25 represented by a line (green line) and intersected the

  x-axis at point (25 , 0) and the y- axis at point (0 , 25)

# x + 2y ≥ 30 represented by a line (blue line) and intersected the

  x-axis at point (30 , 0) and the y-axis at point (0 , 15)

- The three lines intersect each other in three points

# The blue and purple lines intersected in point (0 , 15)

# The green and the purple lines intersected in point (10 , 15)

# The green and the blue lines intersected in point (20 , 5)

- The three lines bounded the feasible region

∴ The vertices feasible region are (0 , 15) , (10 , 15) , (20 , 5)

- To find the minimum value of the objective function C = 4x + 9y,

  substitute the three vertices of the feasible region in C and chose

  the least answer

∵ C = 4x + 9y

- Use point (0 , 15)

∴ C = 4(0) + 9(15) = 0 + 135 = 135

- Use point (10 , 15)

∴ C = 4(10) + 9(15) = 40 + 135 = 175

- Use point (20 , 5)

∴ C = 4(40) + 9(5) = 80 + 45 = 125

- From all answers the least value is 125

∴ The minimum value of the objective function C is 125

6 0
3 years ago
Read 2 more answers
What is the value of y?
Inessa [10]
I think it’s b but I’m not sure
3 0
3 years ago
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Need help please...........
Katen [24]
The missing angle is 49 :)
8 0
2 years ago
Read 2 more answers
How do I find the values of these
skad [1K]
Since the triangles are similar, then 32 = x+7 those two angles are too
solve for "x"

now using proportions   \bf \cfrac{\textit{small triangle}}{\textit{large triangle}}\qquad \cfrac{JK}{18}=\cfrac{12}{12+10}

solve for JK

\bf \cfrac{\textit{small triangle}}{\textit{large triangle}}\qquad \cfrac{12}{12+10}=\cfrac{9}{9+KG}\implies 12(9+KG)=(22)9
\\\\\\
108+9KG=198

solve for KG

the scale factor of the perimeter of both triangles is just the same as the ratio of the sides, or \bf \cfrac{12}{12+10}

3 0
2 years ago
What is the range of the function f(x) = 2x +4 when the domain is {-2, 0, 3}?
Vladimir79 [104]

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>.</em><em>.</em>

<em>Hope </em><em>it</em><em> </em><em>will</em><em> </em><em>be</em><em> </em><em>helpful</em><em> </em><em>to</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em>

7 0
2 years ago
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