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3 years ago

9

An online retailer wants to estimate the number of visitors that click on their advertisement from a particular website. Of 978

page views in a day, 8% of the users clicked on the advertisement. Create a 90% confidence interval for the population proportion of visitors that click on the advertisement.

1 answer:

bonufazy [111]3 years ago

4 0

Answer:

(0.0657,0.0943) is the 90% confidence interval for the population proportion of visitors that click on the advertisement.

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 978

Percentage of users that clicked on advertisement = 8%

Sample proportion:

$\hat{p} = 0.08$

90% Confidence interval:

$\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$z_{critical}\text{ at}~\alpha_{0.10} = 1.645$

Putting the values, we get:

$0.08\pm 1.645(\sqrt{\dfrac{0.08(1-0.08)}{978}})\\\\= 0.08\pm 0.0142\\\\=(0.0658,0.0942) = (6.57\%,9.43\%)$

(0.0657,0.0943) is the 90% confidence interval for the population proportion of visitors that click on the advertisement.

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3. A balancing balloon toy is in the shape of a hemisphere (half-sphere) attached to the base of a cone. If the toy is 4ft tall

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Answer:

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Step-by-step explanation:

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In this problem, the wide of the toy is equal to the diameter of the hemisphere

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The volume of the cone is given by

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we know that

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4 years ago

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Given:

Either has a school certificate or diploma or even both = 20 people

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We know that,

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$n(A\cap B')=n(A)-n(A\cap B)$

$n(A\cap B')=14-5$

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Therefore, 9 people have a school certificate only.

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enyata [817]

I hope this helps you

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