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Viktor [21]
3 years ago
13

How many quarts are there in 10 1/2 Gallons

Mathematics
2 answers:
ser-zykov [4K]3 years ago
7 0
The Answer Is 42 Quarts.


1 Gallon = 4 Quarts
10 x 4 = 40
11 x 4 = 44
So, 42 Is The Median Between Those Two Numbers.

40 Plus 2 = 42
umka2103 [35]3 years ago
4 0
42 quarts is the answer
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It would take 3 bottles. 25 twelve-ounce cups equals out to 300 ounces. There is only 128 ounces in a gallon. 
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ms jones has 754 cookies she wants to give to 5 teachers at thre school. how many cookies does each friend get?
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The data below represent the ages of people working at a store.
Slav-nsk [51]

Answer:

The first step is sort the values on increasing order and we got:

18, 18, 19, 19, 19, 20, 22, 23. 25,  26, 31

And in order to find the first quartile we can separate the first 5 lowest values from the largest 5 values. And for this case we focus on these values:

18, 18, 19, 19, 19

And if we find the median of the last 5 values we can find the first quartile and we got:

Q_1 = 19

The best answer would be:

19

Step-by-step explanation:

For this problem we have the following dataset:

18, 26, 19, 25, 19, 23, 31, 22, 19, 18, 20

The first step is sort the values on increasing order and we got:

18, 18, 19, 19, 19, 20, 22, 23. 25,  26, 31

And in order to find the first quartile we can separate the first 5 lowest values from the largest 5 values. And for this case we focus on these values:

18, 18, 19, 19, 19

And if we find the median of the last 5 values we can find the first quartile and we got:

Q_1 = 19

The best answer would be:

19

4 0
3 years ago
Help me plz I’m struggling with this
elena-s [515]

Answer:

AC = 8√3       AC = 7.65          

A = 43.17°       AB = 16.8

B = 46.83°      B = 27°

Step-by-step explanation:

FIRST TRIANGLE

by using pythagorus theorem:

Hypo² = Base² + height²

19² = 13² + AC²

AC² = 19² - 13²

AC² = 192

AC = √192

AC = 8√3

sinФ =base/hypo

sin A = 13/19

A = sin^-1 (13/19)

A = 43.17°

43.17°+ B + 90° =180 (sum of angles of triangle)

B = 180° - 133.17°

  = 46.83°

<h3>SECOND TRIANGLE</h3>

TanФ = base/height

Tan 63° = 15 / AC

1.96 = 15/AC

AC = 15/1.96

AC = 7.65

AB² = AC² + BC²

AB² = 7.65² + 15²

AB² = 283.5

AB = √283.5

AB = 16.8

tan B = AC /BC

tanФ = 7.65/15

tanФ = 0.51

Ф = tan^-1(0.51)

B = 27°

3 0
3 years ago
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