It requires a circular movement to either left or right to get the figure on the right side of the paper.
1+2=3. 4/10+2/10=6/10. 3+ 6/10=3 6/10
The solution of the system of equation is the intersection point of the two quadratic equations, so we need to equate both equations, that is,
So, by moving the term -3x^3+20 to the left hand side, we have
Then, in order to solve this equation, we can apply the quadratic formula
In our case, a=5, b=-3 and c=-30. So we get
which gives
By substituting these points into one of the functions, we have
and
Then, by rounding these numbers to the nearest tenth, we have the following points:
Therefore, the answer is the last option
the correct question is
<span>The length of a rectangle is represented by 4a + 3b, and its width is represented by 3a-2b. Write a polynomial for the perimeter of the rectangle. What is the minimum perimeter of the rectangle if a=12 and b is a non-zero </span>whole number?
we know that
Perimeter of a rectangle=2*[length + width]
length=(4a+3b)
width=3a-2b
so
P=2*[(4a+3b)+(3a-2b)]-----> P=2*[7a+b]-----> P=14a+2b
the answer part a) is
A polynomial for the perimeter of the rectangle is P=14a+2b
Part b)
for a=12
P=14*12+2b---------> P=168+2b
<span>the minimum perimeter of the rectangle is for b=1
</span>so
P=168+2*1-----> P=170 units
the answer part b) is
the minimum perimeter of the rectangle is 170 units
Answer:
Step-by-step explanation:
Since the picture isn't given. I have no idea what the radius or diameter is and as such, have no definite answer for you.
However, from the question, if he's to run round the circular track once, then he must have run a total of
2πr meters, with r being the radius.
Now, the question says that he ran round the track 10 times, this means that whatever value we get there, for 1 trial, we multiply it by 10, to get the value for 10 trials. Essentially,
10 * 2πr
The value gotten is the needed answer. All you have to do is substitute r for the value you have in your diagram. We already know that π is 3.142
