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3 years ago

What is 41 divided by 17 as a decimal rounded to the nearest tenth.

Mathematics

1 answer:

emmasim [6.3K]3 years ago

5 0

2.4 sould be your answer sorry if u no longer need this answered

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laws of Sines with find the angle. Find each measurement indicated. Round your answers to the nearest tenth. Part 4

lukranit [14]

Answer:

10. Not enough information

11. B ≈ 12.0°

12. A ≈ 34.1°

Step-by-step explanation:

10. Not enough information

11.

We need to use the Law of Sines, which states that for a triangle with lengths a, b, and c and angles A, B, and C:

$\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}$

Here, we can say that AB = c = 38, C = 128, and AC = b = 10. Plug these in to find B:

$\frac{b}{sinB} =\frac{c}{sinC}$

$\frac{10}{sinB} =\frac{38}{sin128}$

Solve for B:

B ≈ 12.0°

12.

Use the Law of Sines as above.

$\frac{a}{sinA} =\frac{b}{sinB}$

$\frac{23}{sinA} =\frac{28}{sin(43)}$

Solve for A:

A ≈ 34.1°

6 0

3 years ago

A cereal manufacturer produces cereal in boxes having a labeled weight of 15.7 ounces. Suppose that a random sample of 31 boxes

taurus [48]

Answer:

$t=\frac{16.14-15.7}{\frac{1.18}{\sqrt{31}}}=2.076$

$p_v =P(t_{(30)}>2.076)=0.0233$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the true mean for the weigths of cereal boxes is higher than 15.7 at 5% of signficance.

Step-by-step explanation:

Data given and notation

$\bar X=16.14$ represent the sample mean

$s=1.18$ represent the sample standard deviation

$n=31$ sample size

$\mu_o =15.7$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is higher than 15.7 or no, the system of hypothesis would be:

Null hypothesis: $\mu \leq 15.7$

Alternative hypothesis: $\mu > 15.7$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{16.14-15.7}{\frac{1.18}{\sqrt{31}}}=2.076$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=31-1=30$

Since is a one side test the p value would be:

$p_v =P(t_{(30)}>2.076)=0.0233$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence toreject the null hypothesis, and we can conclude that the true mean for the weigths of cereal boxes is higher than 15.7 at 5% of signficance.

4 0

3 years ago

Solve for b. −13b=9 plees help

Brilliant_brown [7]

−13b=9
divide both sides by -13
−13b/-13 =9/-13
simplify
b = -9/13

5 0

3 years ago

Read 2 more answers

I equals 3.14, T equals 5.71, P equals three years. I divided by T divided by P equals?

Lunna [17]

3.14/5.71=0.18330414466 years hope this hepls

5 0

3 years ago

Determine which of the lines are parallel and which of the lines are perpendicular. Select all of the statements that are true.

slega [8]

Answers:

Line A is parallel to line D.

Line A is perpendicular to line C.

Line C is perpendicular to line D.

=====================================================

Explanation:

Let's use the slope formula to calculate the slope of the line through (-1,-17) and (3,11)

$(x_1,y_1) = (-1,-17) \text{ and } (x_2,y_2) = (3,11)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{11 - (-17)}{3 - (-1)}\\\\m = \frac{11 + 17}{3 + 1}\\\\m = \frac{28}{4}\\\\m = 7\\\\$

The slope of line A is 7

-------------

Now let's find the slope of line B.

$(x_1,y_1) = (0,4) \text{ and } (x_2,y_2) = (7,-5)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{-5 - 4}{7 - 0}\\\\m = -\frac{9}{7}\\\\$

-------------

Now onto line C.

$(x_1,y_1) = (7,1) \text{ and } (x_2,y_2) = (0,2)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{2 - 1}{0 - 7}\\\\m = \frac{1}{-7}\\\\m = -\frac{1}{7}\\\\$

-------------

Lastly we have line D.

$(x_1,y_1) = (-1,-6) \text{ and } (x_2,y_2) = (1,8)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{8 - (-6)}{1 - (-1)}\\\\m = \frac{8 + 6}{1 + 1}\\\\m = \frac{14}{2}\\\\m = 7\\\\$

------------------------------

Here's a summary of the slopes we found

$\begin{array}{|c|c|} \cline{1-2}\text{Line} & \text{Slope}\\\cline{1-2}\text{A} & 7\\\cline{1-2}\text{B} & -9/7\\\cline{1-2}\text{C} & -1/7\\\cline{1-2}\text{D} & 7\\\cline{1-2}\end{array}$

Recall that parallel lines have equal slopes, but different y intercepts. This fact makes Line A parallel to line D.

Lines A and C are perpendicular to one another, because the slopes 7 and -1/7 multiply to -1. In other words, -1/7 is the negative reciprocal of 7, and vice versa. These two lines form a 90 degree angle.

Lines C and D are perpendicular for the same reasoning as the previous paragraph.

Line B unfortunately is neither parallel nor perpendicular to any of the other lines mentioned.

You can use a graphing tool like Desmos or GeoGebra to verify these answers.

6 0

1 year ago