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andreev551 [17]

3 years ago

12

The height of a wave in California varies directly with the seconds that pass by. At 4 seconds, the wave is 6 feet high. Find th

e constant of variation.

1 answer:

alex41 [277]3 years ago

5 0

K=3/2 Hope this help you

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kow [346]

Step-by-step explanation:

please teach me in an example so I can help you. Sorry for not getting the answer ask another person if possible.

3 0

3 years ago

3/4 cup of sugar is needed to make six muffins. How much sugar is in each muffin?

tia_tia [17]

1/8 cup of sugar in each mufin

4 0

3 years ago

(k) is 1/8. What is the value of y when x is 12?

mafiozo [28]

If the equation is kx= y then when x = 12 y would = 1.5

8 0

3 years ago

As of July 1, 2014, the population of India was about 1,267,000,000. How can you write this number in scientific notation?

skelet666 [1.2K]

Answer:

1 I think its 1.267000000

Step-by-step explanation:

4 0

3 years ago

Use the chain rule calculate dw/dr , dw/ds and dw/dt

Liono4ka [1.6K]

Answer:

$\frac{dw}{dr} = \frac{8\cdot r}{4\cdot r^{2}-t^{2}+5\cdot s^{2}}$ , $\frac{dw}{ds} = \frac{10\cdot s}{4\cdot r^{2}-t^{2}+5\cdot s^{2}}$ , $\frac{dw}{dt} = -\frac{2\cdot t}{4\cdot r^{2}-t^{2}+5\cdot s^{2}}$

Step-by-step explanation:

We proceed to derive each expression by rule of chain. Let be $w = \ln (x+2\cdot y + 3\cdot z)$ , $x = r^{2}+t^{2}$ , $y = s^{2}-t^{2}$ and $z = r^{2}+s^{2}$ :

$\frac{dw}{dr} = \frac{\frac{dx}{dr}+2\cdot \frac{dy}{dr} +3\cdot \frac{dz}{dr} }{x+2\cdot y + 3\cdot z}$

$\frac{dx}{dr} = 2\cdot r$

$\frac{dy}{dr} = 0$

$\frac{dz}{dr} = 2\cdot r$

$\frac{dw}{dr} = \frac{8\cdot r}{(r^{2}+t^{2})+2\cdot (s^{2}-t^{2})+3\cdot (r^{2}+s^{2})}$

$\frac{dw}{dr} = \frac{8\cdot r}{4\cdot r^{2}-t^{2}+5\cdot s^{2}}$ (1)

$\frac{dw}{ds} = \frac{\frac{dx}{ds}+2\cdot \frac{dy}{ds} +3\cdot \frac{dz}{ds} }{x+2\cdot y + 3\cdot z}$

$\frac{dx}{ds} = 0$

$\frac{dy}{ds} = 2\cdot s$

$\frac{dz}{ds} = 2\cdot s$

$\frac{dw}{ds} = \frac{10\cdot s}{(r^{2}+t^{2})+2\cdot (s^{2}-t^{2})+3\cdot (r^{2}+s^{2})}$

$\frac{dw}{ds} = \frac{10\cdot s}{4\cdot r^{2}-t^{2}+5\cdot s^{2}}$ (2)

$\frac{dw}{dt} = \frac{\frac{dx}{dt}+2\cdot \frac{dy}{dt} +3\cdot \frac{dz}{dt} }{x+2\cdot y + 3\cdot z}$

$\frac{dx}{dt} = 2\cdot t$

$\frac{dy}{dt} = -2\cdot t$

$\frac{dz}{dt} = 0$

$\frac{dw}{dt} = -\frac{2\cdot t}{(r^{2}+t^{2})+2\cdot (s^{2}-t^{2})+3\cdot (r^{2}+s^{2})}$

$\frac{dw}{dt} = -\frac{2\cdot t}{4\cdot r^{2}-t^{2}+5\cdot s^{2}}$ (3)

7 0

3 years ago