Sqrt(x+4-3)=1
sqrt (x+1) = 1
x+1 = 1^2
x=1-1
x=0
This is how you would get x=0
Hope I helped :)
The cross product of two vectors gives a third vector
![\mathbf v](https://tex.z-dn.net/?f=%5Cmathbf%20v)
that is orthogonal to the first two.
![\mathbf v=(\vec i+\vec j+\vec k)\times(4\,\vec i+\vec k)=\begin{vmatrix}\vec i&\vec j&\vec k\\1&1&1\\4&0&1\end{vmatrix}=\vec i+3\,\vec j-4\,\vec k](https://tex.z-dn.net/?f=%5Cmathbf%20v%3D%28%5Cvec%20i%2B%5Cvec%20j%2B%5Cvec%20k%29%5Ctimes%284%5C%2C%5Cvec%20i%2B%5Cvec%20k%29%3D%5Cbegin%7Bvmatrix%7D%5Cvec%20i%26%5Cvec%20j%26%5Cvec%20k%5C%5C1%261%261%5C%5C4%260%261%5Cend%7Bvmatrix%7D%3D%5Cvec%20i%2B3%5C%2C%5Cvec%20j-4%5C%2C%5Cvec%20k)
Normalize this vector by dividing it by its norm:
![\dfrac{\mathbf v}{\|\mathbf v\|}=\dfrac{\vec i+3\,\vec j-4\,\vec k}{\sqrt{1^2+3^2+(-4)^2}}=\dfrac1{\sqrt{26}}(\vec i+3\,\vec j-4\vec k)](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathbf%20v%7D%7B%5C%7C%5Cmathbf%20v%5C%7C%7D%3D%5Cdfrac%7B%5Cvec%20i%2B3%5C%2C%5Cvec%20j-4%5C%2C%5Cvec%20k%7D%7B%5Csqrt%7B1%5E2%2B3%5E2%2B%28-4%29%5E2%7D%7D%3D%5Cdfrac1%7B%5Csqrt%7B26%7D%7D%28%5Cvec%20i%2B3%5C%2C%5Cvec%20j-4%5Cvec%20k%29)
To get another vector orthogonal to the first two, you can just change the sign and use
![-\mathbf v](https://tex.z-dn.net/?f=-%5Cmathbf%20v)
.
Answer:
2, 3, 5, 7
Step-by-step explanation:
prime numbers between 1 to 10 are 2,3,5,7. it's very easy. 1 is not prime number because it behave as both prime and composite.
Answer:
Four (4) pounds
Step-by-step explanation:
Because we required two (2) pounds to stretch the spring eight (8) inches, we need double the force to stretch it sixteen (16) inches. Sixteen is just double the original amount, meaning we need four (4) pounds to stretch the spring sixteen inches.
Hope this helps!