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kolbaska11 [484]

4 years ago

13

Write 54.9 % as a decimal

2 answers:

algol [13]4 years ago

8 0

$54.9=0.549$

Hope this helps!

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Juliette [100K]3 years ago

3 0

$p\%=\dfrac{p}{100}\\\\54.9\%=\dfrac{54.9}{100}=\dfrac{54.9\cdot10}{100\cdot10}=\dfrac{549}{1000}=0.549$

$Answer:\ \boxed{54.9\%=0.549}$

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a taxi driver charges a fixed of r to a passenger. In addition, the taxi driver charges a rate of m for each mile driven. Write

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R=fixed rate
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T (n) =mn+r

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4 years ago

n200080 [17]

Answer:

See below

Step-by-step explanation:

<u>Zeroes</u>

$f(x)=2(x-1)(x+3)$

$0=2(x-1)(x+3)$

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$x=1$ and $x=-3$

$(1,0)$ and $(-3,0)$

<u>Axis of Symmetry</u>

$f(x)=2(x-1)(x+3)$

$y=2(x-1)(x+3)$

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$y+2(4)=2(x^2+2x-3+4)$

$y+8=2(x^2+2x+1)$

$y+8=2(x+1)^2$

$y=2(x+1)^2-8$

$y=a(x-h)^2+k$

$x=h$

$x=-1$

<u>Vertex</u>

$y=a(x-h)^2+k$

$y=2(x+1)^2-8$

$(h,k)\rightarrow(-1,-8)$

<u>Y-intercept</u>

$f(x)=2(x-1)(x+3)$

$f(0)=2(0-1)(0+3)$

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Please review the attached graph for a visual of these key features.

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3 years ago

Question 1: The diagonal of a rectangle, with base x, remains at a fixed

kramer

We have that The height changing rate when the length of the base is 2 cm

$dh/dt=-7.2cm/s$

From the question we are told

The diagonal of a rectangle, with base x, remains at a fixed value of 3cm. If the base is increasing at a rate of 8 cm/s. at what rate is the height changing when the length of the base is 2 cm?

Generally the Pythagoras equation for the triangle is mathematically given

as

$r^2=h^2+x^2$

With r=3

Therefore

dx/dt=8cm/s

Hence

$2rdr/dt=2hdh/dt+2xdx/dt\\\\\dh/dt=\frac{-x}{r^2-x^2}dx/dt$

We have

$dh/dt=-2/\sqrt{5}(8)\\\\dh/dt=-7.2cm/s$

Therefore

The height changing rate when the length of the base is 2 cm

$dh/dt=-7.2cm/s$

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3 years ago

The price tag on the remote-controlled helicopter said $79. If Jimmy buys the

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Step-by-step explanation:

79×0.08 = 6.32 (tax)

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A keyboard that costs $400 is marked down 10% for a sale. What is the sale price of the keyboard?

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The sale price is $360

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3 years ago