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Stella [2.4K]
3 years ago
14

How many moles of aqueous ions will be produced from the dissolution of 1.0 mole of Na3[Fe(Cl)6] in water?

Chemistry
1 answer:
pentagon [3]3 years ago
5 0

Answer:

four moles could be produced

Explanation:

The computation of the number of moles for producing from the dissolution is shown below:

Given that

Na_3[Fe(Cl)_6]

It could be disassociated as

Na_3[Fe(Cl)_6] \leftrightharpoons 3Na^{+} + [Fe(Cl)_6]^{-3}

Therefore 3Na ^{+} ions and 1 [Fe(Cl)_6]^{-3} could be generated

And from 1 mole of Na_3[Fe(Cl)_6],

= 3 + 1

= 4 moles

Therefore four moles could be produced

By considering the above calculation we can easily determine the number of moles

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Assume the volume of the crew cabin is 74,000 L. The pressure is maintained at around 1.00 atm, ideally with an 80% nitrogen and
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Answer:

The number of moles of oxygen present in the crew cabin at any given time is 615.309 moles

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From the universal gas equation, we have;

n = \frac{P \times V}{R  \times  T}

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n = Number of moles  of oxygen

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V = Volume of oxygen = 14,800 L

T = Temperature = 293.15 K

R = Universal Gas Constant = 0.08205 L·atm/(mol·K)

Plugging in the values, we have;

n = \frac{1 \times 14,800 }{0.08205   \times  293.15 } = 615.309 \, moles

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