Answer:
<em>The </em><em>SI </em><em>unit </em><em>of </em><em>density </em><em>is </em><em>g/</em><em>cm³</em><em> </em><em>or </em><em> </em><em>kg/</em><em>m³</em>
Answer:(–4.5, –2.5)
(4.5, 6)
(1.3, 3.5)
Step-by-step explanation:
The coordinates of X would be X'(-4, -5).
The equation would be P(x,y) -> P'(-x, y) so you would make the x-coordinate a negative number and keep the y-coordinate the same.
Answer:
Probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is 0.1515.
Step-by-step explanation:
We are given that the amount a Niffler can hold in their pouch is approximately normally distributed with a mean of 25 pounds of shiny objects and a standard deviation of 6.8 pounds.
Let X = <u><em>amount a Niffler can hold in their pouch</em></u>
So, X ~ Normal(
)
The z score probability distribution for normal distribution is given by;
Z =
~ N(0,1)
where,
= population mean = 25 pounds
= standard deviation = 6.8 pounds
Now, the probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is given by = P(X > 32 pounds)
P(X > 32 pounds) = P(
>
) = P(Z > 1.03) = 1 - P(Z
1.03)
= 1 - 0.8485 = 0.1515
<em>The above probability is calculated by looking at the value of x = 1.03 in the z table which has an area of 0.8485.</em>
<em />
Hence, the probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is 0.1515.
67593 increased bye 10430 is 78,023