Question

A square has a side length x and a circle has a radius (x-1). At what value of x will the two figures have the same area?

Answer 1

Answer:

B

Step-by-step explanation:

The area of the square can be calculated using S^2 = x^2

The area of the circle is pi * r^2

= 22/7 * (x-1)^2

= 22(x-1)^2/7

So we need the value of x, that will make;

x^2 = 22(x-1)^2/7

In this kind of scenario, since we have options, it is best to test values instead of going through long calculations

Let’s try 2.29

So;

2.29^2 = 22/7(2.29-1)^2

5.2441 = 5.23

So close , but let’s see if any other value will

give us a closer value

Let’s work with 1.66

1.66^2 = 22/7(1.66-1)^2

2.7556 = 1.369

This is far from what we need

Let’s try 0.5

0.5^2 = 22/7(0.5-1)^2

Thus gives a negative answer on the right hand side, so no need trying

And lastly 1.25

1.25^2 = 22/7(1.25-1)^2

1.5625 = 0.1946

So the first test still gives the most probable answer to a decimal place accuracy