(y+20)=1(x+10); First, we can find the slope by using the equation y2-y1/x2-x1.
-9+20/1+10 (Accounting for double negatives).
11/11 = 1
The slope of the equation is 1, now we just need to pick a set of points from which we derived the slope from (doesn't matter which) as y1 and x1 in the point-slope equation. (y-y1)=m(x-x1)
Your final answer can either be (y+20)=1(x+10) or (y+9)=1(x-1) but in the context of this question it is (y+20)=1(x+10)
Answer:
x = 7°
<GDH = 112°
<FDH = 192°
<FDE = 135°
Step-by-step explanation:
If DE bisects <GDH this means that <GDE = <EDH
Given <GDE = (8x+1)° and <EDH = (6x+15)° then;
8x+1 = 6x+15
8x-6x = 15-1
2x = 14
x = 7°
Since <GDH = <GDE + <EDH
<GDH = 8x-1+6x+15
<GDH = 14x+14
<GDH = 14(7)+14
<GDH = 98+14
<GDH = 112°
For <FDH,
Note that sum of angle on a straight line is 180°
<FDH = <FDG + <GDE + <EDH
<FDH = <FDG + <GDH
<FDG = 180-(43+8x+1)
<FDG = 180-44-8x = 136-8x
<FDH = 136-8x+112
<FDH = 248-8x
<FDH = 248-8(7)
<FDH = 248-56
<FDH = 192°
For <FDE;
<FDE = <FDG + <GDE
<FDE = 136-8x+8x-1
<FDE = 135°
Hello from MrBillDoesMath!
Answer: No.
Discussion:
Look at the 1st and 4th members of the relation.
(7,2) (7,3)
Treating these as points, a vertical line passes through both of them ( x = 7 is the line) so there is no unique y value corresponding to x =7. So no functional relationship exists between them.
Regards, MrB
Step-by-step explanation:
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Answer:
8
Step-by-step explanation: