Answer
Step-by-step explanation: example
5/(X+2). + 2/(X+1)
Common denominator. Is both (X+2)(X+1)
So the first fraction needs (X+1) since it already has (X+2) the second fraction needs ( X+2)
5(X+1). / (X+2)((X+1) +. 2/(X+2)/(X+1)
So multiply 5 with X then 5 with 1 and 2 times X and 2 times 2
5x+5 + 2x+4 / (X+2)((X+1)
Answer 7x+9/ (X+2)(X+1)
Answer:
B
Step-by-step explanation:
Step-by-step explanation:
6. 7. 13
18. 10. 28
24. 17. 41
Number 29 would be y=-x +10
Answer:
The correct option is (A).
Step-by-step explanation:
If the reduced row echelon form of the coefficient matrix of a linear system of equations in four different variables has a pivot, i.e. 1, in each column, then the reduced row echelon form of the coefficient matrix is say A is an identity matrix, here I₄, since there are 4 variables.
![\left[\begin{array}{cccc}1&0&0&0\\0&1&0&0\\0&0&1&0\\0&0&0&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%260%260%5C%5C0%261%260%260%5C%5C0%260%261%260%5C%5C0%260%260%261%5Cend%7Barray%7D%5Cright%5D)
Then the corresponding augmented matrix [ A|B] , where the matrix is the representation of the linear system is AX = B, must be:
![\left[\begin{array}{ccccc}1&0&0&0&a\\0&1&0&0&b\\0&0&1&0&c\\0&0&0&1&d\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccccc%7D1%260%260%260%26a%5C%5C0%261%260%260%26b%5C%5C0%260%261%260%26c%5C%5C0%260%260%261%26d%5Cend%7Barray%7D%5Cright%5D)
Now the given linear system is consistent as the right most column of the augmented matrix is a linear combination of the columns of A as the reduced row echelon form of A has a pivot in each column.
Thus, the correct option is (A).