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AleksandrR [38]
3 years ago
5

Integers help please

Mathematics
2 answers:
masya89 [10]3 years ago
7 0

Answer:

{5}^{ - 13}

Step-by-step explanation:

\frac{ {5}^{ - 5} }{ {5}^{8} }  =  {5}^{ - 5}  \div  {5}^{8}  \\  =  {5}^{ - 5 - 8}  \\  =  {5}^{ - 13}

Harlamova29_29 [7]3 years ago
5 0
The correct answer is 1/5^13
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Piper is at the grocery store and plans on buying cans of soup and frozen dinners, but
Feliz [49]

Answer:

<em>1,500 mg </em>

<em>150c + 450f</em>

Step-by-step explanation:

Each can of soup has 150 mg of sodium and each peach frozen has 450 mg of sodium.

Piper plans to buy some of each product and wants to know how many milligrams of sodium are there in 4 cans of soup and 2 frozen dinners.

Since each can of soup has 150 mg of sodium, 4 cans have 4*150 = 600 mg of sodium.

Each frozen dinner has 450 mg of sodium, thus 2 of them have 2*450 = 900 mg of sodium.

There are 600 + 900 = 1,500 mg of sodium in this combination.

If Piper buys c cans of soup and f frozen dinners, they will have 150c + 450f milligrams of sodium.

8 0
3 years ago
Consider the probabilities of people taking pregnancy tests. Assume that the true probability of pregnancy for all people who ta
Valentin [98]

Using conditional probability, it is found that there is a 0.8462 = 84.62% probability that a woman who gets a positive test result is truly pregnant.

<h3>What is Conditional Probability?</h3>

Conditional probability is the probability of one event happening, considering a previous event. The formula is:

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem, the events are:

  • Event A: Positive test result.
  • Event B: Pregnant.

The probability of a positive test result is composed by:

  • 99% of 10%(truly pregnant).
  • 2% of 90%(not pregnant).

Hence:

P(A) = 0.99(0.1) + 0.02(0.9) = 0.117

The probability of both a positive test result and pregnancy is:

P(A \cap B) = 0.99(0.1)

Hence, the conditional probability is:

P(B|A) = \frac{0.99(0.1)}{0.117} = 0.8462

0.8462 = 84.62% probability that a woman who gets a positive test result is truly pregnant.

You can learn more about conditional probability at brainly.com/question/14398287

7 0
2 years ago
The sum of two rational numbers will always be
telo118 [61]
It's the same as adding 2 fractions the product of 2 rational numbers is rational
6 0
3 years ago
Read 2 more answers
Six friends share 4 pairs equally
lina2011 [118]
Each friend gets two each

6 0
3 years ago
Read 2 more answers
How much percent of 200 miles is in 150 miles
satela [25.4K]
❅ 300%
You can do this by multiplying
Then converting that into a decimal
Then multiplying that by 150
❅Hope this helps!❅
4 0
4 years ago
Read 2 more answers
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