Answer: y= - 4x+18
Step-by-step explanation:
Equation: y=mx+b
***remember: b is the y-intercept and m is the slope.
m=
3= x1
2= x2
6= y1
10=y2
m==
= -4
m=-4
Now we have y=-4x+b , so let's find b.
You can use either (x,y) such as (3,6) or (2,10) point you want..the answer will be the same:
(3,6). y=mx+b or 6=-4 × 3+b, or solving for b: b=6-(-4)(3). b=18.
(2,10). y=mx+b or 10=-4 × 2+b, or solving for b: b=10-(-4)(2). b=18.
Equation of the line: y=-4x+18
Answer:
y = 4x² -19x -5
Step-by-step explanation:
When you graph it (or use an appropriate tool), it can help us to figure out that the equation is:
y = 4x² -19x -5
(Quadratic regression = the process of determining the equation of a parabola that best fits a set of data)
<em>Hope this helps, have a nice day :D</em>
Answer:
a)
b) Since the distribution for X is normal then we know that the distribution for the sample mean is given by:
c)
And we can use the complement rule and we got:
d)
And we can use the complement rule and we got:
e)
And we can use the complement rule and we got:
Step-by-step explanation:
a. If we select a random sample of 50 households, what is the standard error of the mean?
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Let X the random variable that represent the amount of life insurance of a population, and for this case we know the distribution for X is given by:
Where and
If we select a sample size of n =35 the standard error is given by:
b. What is the expected shape of the distribution of the sample mean?
Since the distribution for X is normal then we know that the distribution for the sample mean is given by:
c. What is the likelihood of selecting a sample with a mean of at least $112,000?
For this case we want this probability:
And we can use the z score given by:
And replacing we got:
And we can use the complement rule and we got:
d. What is the likelihood of selecting a sample with a mean of more than $100,000?
For this case we want this probability:
And we can use the z score given by:
And replacing we got:
And we can use the complement rule and we got:
e. Find the likelihood of selecting a sample with a mean of more than $100,000 but less than $112,000
For this case we want this probability:
And we can use the z score given by:
And replacing we got:
And we can use the complement rule and we got: