The square root of x^8 =

2 answers:

Nookie1986 [14]3 years ago

6 0

Simple.....

$x^{4}$

All you have to do is simplify the radical by breaking the radicand up into a product of known factors.

Thus, your answer.

Vladimir [108]3 years ago

5 0

It would be $x^4$

I'm not sure what method you use to do these problems, but if you ever have one like this, it's essentially dividing by 2 for the exponent only. 8/2 is 4, so it's
$x^4$

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SIZIF [17.4K]

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3 years ago

Given the sequence in the table below, determine the sigma notation of the sum for term 4 through term 15.

Naya [18.7K]

It's a geometric sequence.

$4,-12,36,... \\ \\
a_1=4 \\
r=\frac{a_2}{a_1}=\frac{-12}{4}=-3 \\ \\
a_n=a_1 \times r^{n-1} \\
a_n=4 \times (-3)^{n-1} \\
a_n=4 \times (-3)^{-1} \times (-3)^n \\
a_n=4 \times (-\frac{1}{3}) \times (-3)^n \\
a_n=-\frac{4}{3}(-3)^n$

It's the sum for term 4 through term 15.

$\boxed{ \sum\limits_{n=4}^{15} (\frac{4}{3}(-3)^n)}$