U= 9.4m/s
v= -7.4m/s (Negative sign because it is in the opposite direction as he is rolling back)
t= ?
s= ?
a= ?
Now, a= v-u/t
= -7.4-9.4÷3
=-5.6
By the second equation of motion.
s= ut+1÷2at*2 ( *2 is the power)
s= 9.4×3+1÷2×-5.6×3*2
= 28.2 +(-25.2)
=3
Therefore s or the distance travelled is 3m.
To find the interquartile range, you will list the data that is presented in the stem and leaf plot.
Find the median of the data (30.5)
Find the median of the lower half and the median of the upper half.
Subtract these two values.
The data are <u>20</u>, 25, 30, 30, 31, 40, 41, <u>49</u>.
27.5 40.5
40.5-27.5 = 13
The interquartile range is 13.
Answer: (x-5 ) (x-2)
Step-by-step explanation:
Answer:
Step-by-step explanation:
m (x) = (x+ 5) / (x -1) and n(x) = x - 3.
Hence
but n is a function and n = x-3. Now, replace value of n on m (n)
simplify it
since (m . n) (x) is a fraction function, its domain will be all x such that the denominator is NOT 0. That is
among options, only C has the same denominator with 
Hence their domains are the same.
If by base of 10, you mean that the diameter of the base is 10, then the radius of the base is 5.
volume = pi * r^2 * h
volume = pi * 5^2 * 10
volume = 250pi, or approximately 785
