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Rzqust [24]
3 years ago
6

A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 50.0 and 60.

0 minutes. Find the probability that a given class period runs between 51.25 and 51.5 minutes.
Mathematics
1 answer:
Artist 52 [7]3 years ago
3 0

Answer: 0.0250

Step-by-step explanation:

Given : A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 50.0 and 60.0 minutes.

We know that the uniform distribution is also known as rectangular distribution.

Density function for uniform distribution :f(x)=\dfrac{1}{b-a}

=\dfrac{1}{60-50}=\dfrac{1}{10}

Now, the probability that a given class period runs between 51.25 and 51.5 minutes :-

\int^{51.5}_{51.25}f(x)\ d(x)\\\\ \int^{51.5}_{51.25}\dfrac{1}{10}\ dx\\\\=\dfrac{1}{10} [x]^{51.5}_{51.25}\\\\=\dfrac{1}{10}(51.5-51.25)=0.0250

Hence, the probability that a given class period runs between 51.25 and 51.5 minutes = 0.0250

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Hello! I can help you with this!

a. To find out how much Mary saved, we will have to subtract the sale price from the original price, and then add up the difference to find how much she saved. 62 - 48 is 14. 46 - 34 is 12. 14 + 12 = 26. Mary saved $26 by buying at the sale item price.

b. To find the amount of discount, we can write and solve a proportion, by setting it up like this: change/original = x/100. Change is the distance between two numbers and the original is the previous price. If you know about proportions, you cross multiply the values, and then divide each side by a number to isolate "x". If you solve each proportion correctly, here are your answers for each item:

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