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Alchen [17]
3 years ago
12

Help me lol please and thank you

Mathematics
1 answer:
Sindrei [870]3 years ago
5 0
Well the opposite of addition is subtraction
to find n move 27 to the other side which makes it negative
15+ (-27) =-12
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Which of the following triangles are right triangles? select all apply
Alex Ar [27]

Answer:

The following Triangles are Right Triangles:

1.  Δ ABC Where AB = 76 in, BC = 357 in, and AC = 365 in.

2. Δ MIT Where MI = 123 cm, IT = 836 cm, and MT = 845 cm.

3. Δ MEL Where ME = 20 ft, EL = 99 ft, and ML = 101 ft.

Step-by-step explanation:

For a Triangle to be a Right Triangle it must Satisfy Pythagoras theorem.

i.e.

(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}

For Δ ABC Where AB = 76 in, BC = 357 in, and AC = 365 in.

AC² = 365² = 133225

AB² + BC² = 76² + 357² = 1333225

∴  AC² = AB² + BC²

Hence Δ ABC a Right Triangle.

For Δ MIT Where MI = 123 cm, IT = 836 cm, and MT = 845 cm.

MT² = 845² = 71405

MI² + IT² = 123² + 836² = 714025

∴ MT² = MI² + IT²

Hence Δ MIT a Right Triangle.

For  Δ MEL Where ME = 20 ft, EL = 99 ft, and ML = 101 ft.

ML² = 101² = 10201

ME² + EL² = 20² + 99² = 10201

∴ ML² = ME² + EL²

Hence Δ MEL a Right Triangle.

7 0
3 years ago
Factor the following expression.<br> x2 + 4x - 5
sashaice [31]

Answer:(x+5)(x-1)

Step-by-step explanation:

4 0
3 years ago
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In ΔABC, m∠ACB = 90°, CD ⊥ AB and m∠ACD = 45°. Find: CD, if BC = 3 in
IRISSAK [1]
We can find m∠BCD like follows: m∠BCD=90°-45°=45<span>°
Now, m</span><span>∠DBC= 180°-(90°+45°)=45°

Remember that </span>sin \alpha = \frac{opposite leg}{hypotenuse}, so oppositeleg=(hypotenuse)(sin \alpha )

We know that hypotenuse= BC= 3in and \alpha=∠DBC)=45°, so replacing the values we get:
CD=3sin(45)=2.12

We can conclude that the segment CD is 2.12 in
4 0
3 years ago
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Which is a true statement about the given ratios?
saul85 [17]
The bottoms are all multiples of seven
4 0
3 years ago
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10) through: (3.-1). slope = -1​
Naddika [18.5K]

Answer:

y = -x + 2

Step-by-step explanation:

The question is to find the equation of the line going through the points (3,-1) and has a slope of -1.

First, the equation of a line is given as:

Equation = y = mx + b

Where

m is the slope

b is the y-intercept (y-axis cutting point)

We know the slope, so the equation becomes:

y = mx + b

y = -1x + b

y = -x + b

Now the point given is in the form (x,y), so

x = 3

y = -1

We substitute and find b:

y = -x + b

-1 = -3 + b

-1 + 3 = b

b = 2

Final Equation:

y = -x + 2

6 0
3 years ago
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