Answer:
The question is incorrect. Are you multiplying these polynomials? if so we will not get a value for x.
The average density of the rod is 0.704 kg/m.
For given question,
We have been given the linear density in a rod 5 m long is 10 / x + 4 kg/m, where x is measured in meters from one end of the rod.
We need to find the
The length of rod is, L = 5 m.
The linear density of rod is, ρ = 10/( x + 4) kg/m
To find the average density we need to integrate the linear density from x₁ = 0 to x₂ = 5,
The expression for the average density is given as,
⇒ ρ'
......................(1)
Using u = x + 4
du = dx
u₁ = x₁ + 4
u₁ = 0 + 4
u₁ = 4
and
u₂ = x₂ + 4
u₂ = 5 + 4
u₂ = 9
By entering the values above into (1), we have:
⇒ ρ'
= 0.704
Thus, we can conclude that the average density of the rod is 0.704 kg/m.
Learn more about the average density here:
brainly.com/question/15118421
#SPJ4
Y⁴/³ x y³/³
The answer is 1 because since the variable "y" has an invisible one in front of it, 1 to the power of anything stays "1".
Hope this helps :)
3x +y = 1
Subtract 3x from each side to find y, as follows:
y = -3x + 1
The first choice is correct.
Answer:
Let's simplify step-by-step.
34(5a−16)−13(6a−3)
Distribute:
=(34)(5a)+(34)(−16)+−2a+1
=154a+−12+−2a+1
Combine Like Terms:
=154a+−12+−2a+1
=(154a+−2a)+(−12+1)
=74a+−11
Answer:
=74a−11