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AveGali [126]
3 years ago
13

If f(x) = -X^3+3x+2. Find f(-1).

Mathematics
1 answer:
Simora [160]3 years ago
4 0

Answer:

idk what kinda work is this dude ?

Step-by-step explanation:

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<u>Question 4</u>

<u />\sin 30^{\circ}=\frac{y}{14\sqrt{3}}\\\\\frac{1}{2}=\frac{y}{14\sqrt{3}}\\\\\boxed{y=7\sqrt{3}}\\\\\\\\\cos 30^{\circ}=\frac{x}{14\sqrt{3}}\\\\\frac{\sqrt{3}}{2}=\frac{x}{14\sqrt{3}}\\\\\boxed{x=21}

<u>Question 5</u>

<u />\cos 45^{\circ}=\frac{x}{28}\\\\\frac{1}{\sqrt{2}}=\frac{x}{28}\\\\x=\frac{28}{\sqrt{2}}\\\\\boxed{x=14\sqrt{2}}\\\\\\\\\sin 45^{\circ}=\frac{y}{28}\\\\\frac{1}{\sqrt{2}}=\frac{y}{28}\\\\y=\frac{28}{\sqrt{2}}\\\\\boxed{y=14\sqrt{2}}

7 0
2 years ago
Help please loves? I'm horrible at math.
11Alexandr11 [23.1K]
The answer is C.  I'm pretty sure of it.

5 0
3 years ago
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John rolls a six-sided number cube twice. What is the probability of getting an even number and then an odd number?
lubasha [3.4K]

Answer:

Option 2 - \text{Probability}=\frac{1}{4}

Step-by-step explanation:

Given : John rolls a six-sided number cube twice.

To find : What is the probability of getting an even number and then an odd number?    

Solution :              

When rolls a six-sided number cube twice

(1,1)  (1,2) (1,3)  (1,4)  (1,5)  (1,6)  

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)  

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)  

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)  

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)  

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)  

Now,  

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

Favorable outcome of getting an even number and then an odd number:

(2,1) (2,3) (2,5) (4,1) (4,3) (4,5) (6,1) (6,3) (6,5)

So, Favorable outcome = 9

Total number of outcome = 36

\text{Probability}=\frac{9}{36}

\text{Probability}=\frac{1}{4}

Therefore, Option 2 is correct.

4 0
3 years ago
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Answer:

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Step-by-step explanation:

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