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natita [175]
3 years ago
7

Please show work!!! An open box is formed by cutting squares with side lengths of 4 inches from each corner of a square piece of

paper.
What is a side length of the original paper if the box has a volume of 784 cubic inches?

A- 14
B-18
C- 26
D- 22
Mathematics
2 answers:
AnnyKZ [126]3 years ago
7 0
The original square of piece of paper, 
<span>with the cutting and folding lines would look like this: </span>
<span>You see 4 congruent squares cut out of the corners. </span>
<span>If the length of the sides of those squares is 4 inches, </span>
<span>then the height of the box will be 4 inches. </span>
<span>Let x be the length (in inches) of the side of the square (the bottom of the box). </span>
<span>The surface area of the bottom (in square inches) is x^2, </span>
<span>and the volume of the box, calculated as area of the bottom times height, </span>
<span>(in cubic inches) is 4x^2 </span>
<span>So 4x^2 = 784---> x^2 = 784/4 ---> x = sqrt 196 = 14. </span>
<span>Answer: </span>
<span>14 inches 
Hope this helps :)

</span>
andre [41]3 years ago
7 0
I would say A or d because when you divide 784/4=196/49/12 so the closes one would be a <span>Since </span>4 inches<span> were </span>cut<span> from </span>each corner<span> of the </span>square piece<span> of </span>paper<span>, we </span>have. H=4<span>. Since the </span>original paper<span> is </span>square<span> and the </span>length cut<span> from </span>each side<span> is the same, the resulting base is still </span>square. L=W. ⇒784=4⋅L⋅W ⇒784=4L2 ⇒196=<span>L2 ⇒L=14. Now, what we want is the </span>length<span> of the </span>original paper<span>.</span>
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