Let
e = Gibson Explorer’s = 20
v = Gibson Flying V’s
So, our problem is
<u>Maximize</u>Money = 80e + 5v<span>
<u>Subject to</u>0 </span>≤ <span>e ≤ 20
</span>0 ≤ v ≤ 20
0 ≤ e + v ≤ 30
In order to solve this problem, we look at the graph (attached), and find the value of Money =80e + 5v at corner points to find the maximum value of money.
(e,v)=(0,0) >> Money = 80e+5v = 80*0+5*0 = 0
(e,v)=(0,20) >> Money = 80e+5v = 80*0+5*20 = 100
(e,v)=(20,0) >> Money = 80e+5v = 80*20+5*0 = 1600
(e,v)=(20,10) >> Money = 80e+5v = 80*20+5*10 = 1650 (maximum)
(e,v)=(10,20) >> Money = 80e+5v = 80*10+5*20 = 900
So Bob can make the
<u>most money = $1,650</u> when he makes and sell
e = <span>Gibson Explorer’s = 20
</span>v = Gibson Flying V’s = 10
Answer:
Step-by-step explanation:
you will read the directions 2x before solving the problem then solve the problem
Answer:
Hey there!
40 is 25% of 120.
We can see that 30 is 25% of 120, because 0.25(120)=30.
Hope this helps :)
Answer:
The Length of <em>JK</em> is 10
Step-by-step explanation:
Because <<em>J </em>is congruent to <<em>L</em> we know that the triangle in question must be isosceles as in an isosceles triangle two angles opposite of each other are equal. (This is also true for equilateral triangles, however, in an equilateral triangle all sides must be congruent, so we can rule equilateral out as <em>LJ </em>is not congruent to <em>KL.) </em>This means that the triangle must be isosceles.
In an isosceles triangle the side opposite each other are congruent, and the angles opposite each other are congruent when split down the line of symmetry.
Therefor, the length of <em>JK </em>must be congruent to the length of <em>KL. </em>In other words if <em>JK </em>= 10, then <em>KL </em>must equal 10 as well.
Answer:
Yes
Step-by-step explanation:
80² + 150² = 170²
6400 + 22500 = 28900
28900 = 28900