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ozzi
3 years ago
13

2.

Mathematics
2 answers:
Svetllana [295]3 years ago
8 0
He works 40 hours a week.
SIZIF [17.4K]3 years ago
5 0
The answer is 40 if you divide 480 by 12 you’ll get 40
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Evaluate:<br> . C=4x? rind the value of c- given thatx = 16<br> pour
Butoxors [25]

Answer:

c=4x

c-4(16)

c=64

Step-by-step explanation:

6 0
3 years ago
3x^2-y^3-y^3-z if x=3, y=-2, and z=-5
Serggg [28]
3(3)^2-(-2)^3-(-2)^3-(-5) = 48

48 is the answer.
5 0
3 years ago
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Neeeeeed heeelp plz!!!
Blababa [14]
                             |
                             |__x_- 4___________              2x³/2x² =x
   2x² + 2x +3        | 2x³ - 6x² +7x +3
                            - (<span>2x³ +2x² +3x)
</span>                                      -8x² +4x  +3                -8x²/2x² = -4
                                    <span>-(-8x² -8x  -12)
</span>                                              12x +15

(x-4) + (12x +15)/(2x² + 2x +3) 
6 0
3 years ago
How many sides does a polygon have if the sum of the measures of the interior angles is 5940
frutty [35]

Answer:

Sorry for my handwriting

5 0
2 years ago
Read 2 more answers
A farmer wants to fence an area of 13.5 million square feet in a rectangular field and then divide it in half with a fence paral
denis23 [38]

Answer:

  F = 3x +(2.7×10^7)/x

Step-by-step explanation:

The formulas for area and perimeter of a rectangle can be used to find the desired function.

<h3>Area</h3>

The area of the rectangle will be the product of its dimensions:

  A = LW

Using the given values, we have ...

  13.5×10^6 = xy

Solving for y gives ...

  y = (13.5×10^6)/x

<h3>Perimeter</h3>

The perimeter of the rectangle is the sum of the side lengths:

  P = 2(L+W) = 2(x+y)

<h3>Fence length</h3>

The total amount of fence required is the perimeter plus one more section that is x feet long.

  F = 2(x +y) +x = 3x +2y

Substituting for y, we have a function of x:

  F = 3x +(2.7×10^7)/x

__

<em>Additional comment</em>

The length of fence required is minimized for x=3000. The overall size of that fenced area is x=3000 ft by y=4500 ft. Each half is 3000 ft by 2250 ft. Half of the total 18000 ft of fence is used for each of the perpendicular directions: 3x=2y=9000 ft.

4 0
2 years ago
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