3 years ago

2^(n-1) = 256 ? Please give me the answer

Mathematics

1 answer:

klemol [59]3 years ago

7 0

Answer:

n = 9

Step-by-step explanation:

Note that

256 = $2^{8}$ , thus

$2^{n-1}$ = $2^{8}$

Since the bases on both sides are equal (2) equate the exponents

n - 1 = 8 ( add 1 to both sides )

n = 9

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2^(n-1) = 256 ? Please give me the answer​

2^(n-1) = 256 ? Please give me the answer