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4 years ago

3 x 2 - (8 + 4) x 5 + 1

Mathematics

1 answer:

PIT_PIT [208]4 years ago

3 0

Answer:

-53

Step-by-step explanation:

6+(-8-4)x5+1

6-60+1

-53

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Given that sectheta = -37/12 what is the value of cottheta for pi/2 < theta< pi?

lys-0071 [83]

Answer:

$cotg(\theta) = -\frac{12}{35}$

Step-by-step explanation:

The cotangent of theta is:

$cotg(\theta) = \frac{\cos{\theta}}{\sin{\theta}}$

For pi/2 < theta< pi

This means that the angle is in the second quadrant. In the second quadrant, the cosine is negative and the sine is positive. This means that the cotangent will be negative.

Secant:

$sec(\theta) = \frac{1}{\cos{\theta}}$

In this question

$sec(\theta) = -\frac{37}{12}$

$-\frac{37}{12} = \frac{1}{\cos{\theta}}$

Using cross multiplication

$-37\cos{\theta} = 12$

$37\cos{\theta} = -12$

$\cos{\theta} = -\frac{12}{37}$

Now we apply the following trigonometric identity:

$\sin{\theta}^{2} + \cos{\theta}^{2} = 1$

$\sin{\theta}^{2} + (-\frac{12}{37})^{2} = 1$

$\sin{\theta}^{2} = 1 - (-\frac{12}{37})^{2}$

$\sin{\theta}^{2} = 1 - \frac{144}{1369}$

$\sin{\theta}^{2} = \frac{1369 - 144}{1369}$

$\sin{\theta} = \pm \sqrt{\frac{1225}{1369}}$

Since the angle is in the second quadrant, the sine is positive.

$\sin{\theta} = \frac{35}{37}$

Finally, the cotangent:

$cotg(\theta) = \frac{\cos{\theta}}{\sin{\theta}}$

$cotg(\theta) = \frac{-\frac{12}{37}}{\frac{35}{37}}$

$cotg(\theta) = -\frac{12}{35}$

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4 years ago

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Abby is 5 feet tall and casts a 4-foot long shadow.If her older brother Ethan is standing next to her and casts a 4.6-foot shado

gregori [183]

Answer:

Ethan is 0.6 feet taller than abby

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3 years ago

Heya ! solve the problem over here - <br><br><img src="https://tex.z-dn.net/?f=%5Clongrightarrow%20%5Ctt2x%20%2B%205%20%3D%2025"

I am Lyosha [343]

Answer: x=10

Step-by-step explanation:

2x-5=25

- 5

--------------------

2x=20

x=10

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1 year ago

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PLEASE SHOW WORK SO I UNDERSTAND THANKS :)<br> -0.3 * -(11)/(30)

Kaylis [27]

Answer:

0.11

Step-by-step explanation:

The answer would be 0.11, i just used a calculator lol

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3 years ago

What is the interquartile range of the data? What is the range of the middle half of the data? What is the range of the data? Wh

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Answer:

There is no data set

Step-by-step explanation:

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3 years ago

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