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bekas [8.4K]
3 years ago
10

What is the interquartile range of the data? What is the range of the middle half of the data? What is the range of the data? Wh

at is the difference between the third quartile and the first quartile?
Mathematics
2 answers:
tigry1 [53]3 years ago
7 0

Answer:

The median of the lower half of a set of data is the lower quartile ( LQ ) or Q1 . The median of the upper half of a set of data is the upper quartile ( UQ ) or Q3 . ... The interquartile range or IQR is the range of the middle half of a set of data. It is the difference between the upper quartile and the lower quartile.

Step-by-step explanation:

spin [16.1K]3 years ago
6 0

Answer:

There is no data set

Step-by-step explanation:

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A square piece of paper 10 cm on a side is rolled to form the lateral surface area of a cylinder and then a top and bottom are a
Anika [276]

Answer:

The surface = pi*10cm2

Step-by-step explanation:

The area of any rectangle is Base *  Height,

We know that the square originally has 10cm High, when is rolled to form a cylinder, it's new shape has a bottom side that is equals to a circle.

The length of a circle is 2*pi*Radio= pi*Diameter.

Since the square has the same length in each side, we know that pi*Diameter= 10cm*pi

The surface (area) of the cylinder is= Base * Height= 10cm*10cm*pi

 

6 0
2 years ago
What is -8 square root of 9 when simplified​
gregori [183]

Answer:

\large\boxed{-8\sqrt9=-24}

Step-by-step explanation:

\sqrt{a}=b\iff b^2=a\\\\\sqrt9=3\ \text{because}\ 3^2=9\\\\-8\sqrt9=-8(3)=-24

7 0
3 years ago
A triangle has side lengths of 9 in, 13 in, and 20 in. What is the measurement of this triangle’s largest angle?
zvonat [6]
1. Given any triangle ABC with sides BC=a, AC=b and AB=c, the following are true :

      i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.

       ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:

       a^{2}=b ^{2}+c ^{2}-2bc(cosA)

2. 

20^{2}=9 ^{2}+13 ^{2}-2*9*13(cosA)

400=81+169-234(cosA)   150=-234(cosA)

cosA=150/-234= -0.641

3. m(A) = Arccos(-0.641)≈130°, 

4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc
4 0
3 years ago
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If U = {all positive integers) and A = {x|x EU and x is an odd positive integer}, which describes AC?
Galina-37 [17]

Answer:

last choice

Step-by-step explanation:

If we are looking at positive integers and we take out the odd ones, the only one's that are left are the even ones.

So last choice.   (Also I assume AC meant the complement of A)

7 0
3 years ago
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Solve this equation<br> 5x+2=3x-20-1x
Rainbow [258]
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6 0
2 years ago
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