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bekas [8.4K]
3 years ago
10

What is the interquartile range of the data? What is the range of the middle half of the data? What is the range of the data? Wh

at is the difference between the third quartile and the first quartile?
Mathematics
2 answers:
tigry1 [53]3 years ago
7 0

Answer:

The median of the lower half of a set of data is the lower quartile ( LQ ) or Q1 . The median of the upper half of a set of data is the upper quartile ( UQ ) or Q3 . ... The interquartile range or IQR is the range of the middle half of a set of data. It is the difference between the upper quartile and the lower quartile.

Step-by-step explanation:

spin [16.1K]3 years ago
6 0

Answer:

There is no data set

Step-by-step explanation:

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8x2 − 5 + 7x4 − 9x − x5
Veseljchak [2.6K]

Answer:

=-\left(x-1\right)\left(x^4-6x^3-6x^2-14x-5\right)

Step-by-step explanation:

Factor out comon Term -1

=-\left(x^5-7x^4-8x^2+9x+5\right)

Factor x^5-7x^4-8x^2+9x+5:\quad \left(x-1\right)\left(x^4-6x^3-6x^2-14x-5\right)

x^5-7x^4-8x^2+9x+5

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a_0=5,\:\quad a_n=1

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Therefore, check the following rational numbers: ±\frac{1,\:5}{1}

\frac{1}{1} is a root of the expression, so factor out x-1

=\left(x-1\right)\frac{x^5-7x^4-8x^2+9x+5}{x-1}

\frac{x^5-7x^4-8x^2+9x+5}{x-1}=x^4-6x^3-6x^2-14x-5

=x^4-6x^3-6x^2-14x-5

=-\left(x-1\right)\left(x^4-6x^3-6x^2-14x-5\right)

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ML would be 2.5 because M is the bisector, splitting those 2 sides into congruent sides.
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3 years ago
Read 2 more answers
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