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bekas [8.4K]
3 years ago
10

What is the interquartile range of the data? What is the range of the middle half of the data? What is the range of the data? Wh

at is the difference between the third quartile and the first quartile?
Mathematics
2 answers:
tigry1 [53]3 years ago
7 0

Answer:

The median of the lower half of a set of data is the lower quartile ( LQ ) or Q1 . The median of the upper half of a set of data is the upper quartile ( UQ ) or Q3 . ... The interquartile range or IQR is the range of the middle half of a set of data. It is the difference between the upper quartile and the lower quartile.

Step-by-step explanation:

spin [16.1K]3 years ago
6 0

Answer:

There is no data set

Step-by-step explanation:

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Christie needs 54.3 Square feet of laminate wood suppose each square foot of laminated wood cost $.60 find the amount she has to
Irina18 [472]
It will cost $33.

Since wood cost $ .60 sq ft, you can assume she needs to buy 55 sq ft because she will need to buy enough to have 54.3 square ft.

55 x $ .60 = $33

$32.58 would be he total for the 54.3 sq ft and .42 cents would be for the left over .7 sq ft that she didn’t use
7 0
2 years ago
How can the common difference between 375-315=30
Firlakuza [10]
Hello :
in the arithemitic sequence  : an = an-1 + 30
3 0
3 years ago
s, of an item is s = c + mc, where c is the cost of the item and m is the percent markup based on cost. What is the formula solv
Kitty [74]

Answer:

Step-by-step explanation:

s=c+mc

s-c=mc

(s-c)/c=m

5 0
3 years ago
The volume of construction work was increased by 60% but the productivity of labor increased by only 25%. By what percent must t
Sergeu [11.5K]

Answer: 28 %

Step-by-step explanation:

Let, Initially,

V be the volume of construction work

r be the productivity of labor  

n be the number of days

x be the number workers.

Thus,  V  = r × n × x   ------------(1)      

Now, According to the question,

The volume of construction work was increased by 60% but the productivity of labor increased by only 25%.

Therefore,

Final volume of the work = 160% of V = 1.6 V

Final productivity = 125% of r = 1.25 r

Also, the time is same in both conditions,

Final time taken = n

Let y be the number of people after changes.

Thus, 1.6 V = 1.25 r × n × y -----(2)

Dividing equation (1) by equation (2)

We get, y = 1.60 x/1.25

Thus, the changes in the number of workers

= \frac{(\frac{1.60x}{1.25}-x) }{x}\times 100

= 0.28 × 100

= 28 %


5 0
3 years ago
How to subtract a negative fraction from a positive fraction?
ikadub [295]
Let's take an example to illustrate this case:

<span>positive fraction = 2/7
</span>
<span>negative fraction = - 3/5

Now we need to subtract  </span><span>- 3/5 from 2/7

Right?

2/7 - (-3/5) = 2/7 + 3/5

here we need to unify the denominators as follows:

the lowest common factor between 7 and 5 is 35
2/7 = 10/35
3/5 = 21/35

Now back to </span><span>2/7 + 3/5:

</span><span><span>2/7 + 3/5 = 10/35 + 21/35 = (10+21)/35 = 31/35

That's it




Hope that helps you</span>
</span>
8 0
3 years ago
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