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bekas [8.4K]
3 years ago
10

What is the interquartile range of the data? What is the range of the middle half of the data? What is the range of the data? Wh

at is the difference between the third quartile and the first quartile?
Mathematics
2 answers:
tigry1 [53]3 years ago
7 0

Answer:

The median of the lower half of a set of data is the lower quartile ( LQ ) or Q1 . The median of the upper half of a set of data is the upper quartile ( UQ ) or Q3 . ... The interquartile range or IQR is the range of the middle half of a set of data. It is the difference between the upper quartile and the lower quartile.

Step-by-step explanation:

spin [16.1K]3 years ago
6 0

Answer:

There is no data set

Step-by-step explanation:

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Branlet will be marked so help out all my gemstones
Jobisdone [24]

Answer:

B is the right answer.

Step-by-step explanation:

56 + 0.08x = 164

0.08x = 164 - 56

0.08x = 108

0.08x/0.08 = 108/0.08

x = 1,350

To confirm that:

56 + 0.08x

56 + 0.08(1,350)

56 + 108

= 164

164 is the answer.

6 0
3 years ago
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Yuri [45]

Answer:

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Step-by-step explanation:

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3 years ago
I need some help i cant figure this out
Luden [163]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
A population has a mean of 300 and a standard deviation of 40. Suppose a sample of size 100 is selected and is used to estimate
bazaltina [42]

Answer:

a: 0.9544 9 within 8 units)

b: 0.9940

Step-by-step explanation:

We have µ = 300 and σ = 40.  The sample size, n = 100.  

For the sample to be within 8 units of the population mean, we would have sample values of 292 and 308, so we want to find:

P(292 < x < 308).

We need to find the z-scores that correspond to these values using the given data.  See attached photo 1 for the calculation of these scores.

We have P(292 < x < 308) = 0.9544

Next we want the probability of the sample mean to be within 11 units of the population mean, so we want the values from 289 to 311.  We want to find

P(289 < x < 311)

We need to find the z-scores that correspond to these values.  See photo 2 for the calculation of these scores.

We have P(289 < x < 311) = 0.9940

5 0
3 years ago
Write the expression shown below with the least amount of terms. <br>8y + 13 - 6y + 3y + 2​
Helga [31]

Answer:

5y + 15

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13 + 2 = 15

4 0
3 years ago
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