
<u>We </u><u>have</u><u>, </u>
- Line segment AB
- The coordinates of the midpoint of line segment AB is ( -8 , 8 )
- Coordinates of one of the end point of the line segment is (-2,20)
Let the coordinates of the end point of the line segment AB be ( x1 , y1 ) and (x2 , y2)
<u>Also</u><u>, </u>
Let the coordinates of midpoint of the line segment AB be ( x, y)
<u>We </u><u>know </u><u>that</u><u>, </u>
For finding the midpoints of line segment we use formula :-

<u>According </u><u>to </u><u>the </u><u>question</u><u>, </u>
- The coordinates of midpoint and one of the end point of line segment AB are ( -8,8) and (-2,-20) .
<u>For </u><u>x </u><u>coordinates </u><u>:</u><u>-</u>





<h3><u>Now</u><u>, </u></h3>
<u>For </u><u>y </u><u>coordinates </u><u>:</u><u>-</u>





Thus, The coordinates of another end points of line segment AB is ( -14 , 36)
Hence, Option A is correct answer
Answer:
y = (-5/2)x + 27
Step-by-step explanation:
Use the point slope formula y = mx + b.
Replace m with -5/2, x with -8 and y with 7:
7 = (-5/2)(8) + b. Find the y-intercept, b:
7 = -20 = b, or b = 27
The equation of this line is y = (-5/2)x + 27.
8/x + 2 is equal to 8/4 + 2.
8/4 = 2
2 + 2 = 4
ANSWER: 4
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Answer:
This is a question you should know in trig.
You should search up how to solve for simple trig functions
The cos of 60 degrees is 1/2 just because you asked