Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of
0 and a standard deviation of 1. Find the probability that a given score is less than 1.99 and draw a sketch of the region.
1 answer:
Answer:
Step-by-step explanation:
To find this probability, we shall be using the z-score route
Mathematically ;
z-score = (x -mean)/SD
From the question, x = 1.99, mean = 0 and SD = 1
So z = (1.99-0)/1 = 1.99
So the probability we want to calculate is;
P(z<1.99)
This value can be obtained from the standard normal distribution table.
P(z < 1.99) = 0.9767
The sketch of the region is as shown as in the attachment.
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Answer:
5.1 cm
Step-by-step explanation:
(Probable) Question;
Given a circle with center <em>O</em> and radius 2.4 cm.<em> P</em> is a point on the tangent that touches the circle at point <em>Q</em>, such that the length of the tangent from <em>P </em>to <em>Q</em> is 4.5 cm. Find the length of OP
The given parameters are;
The radius of the circle with enter at <em>O</em>, = 2.4 cm
The length of the tangent from<em> P</em> to the circle at point <em>Q, </em> = 4.5 cm
The length of OP = Required
By Pythagoras's theorem, we have;
² =
² +
²
∴ ² = 2.4² + 4.5² = 26.01
= √26.01 = 5.1
The length of OP = 5.1 cm