Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of
0 and a standard deviation of 1. Find the probability that a given score is less than 1.99 and draw a sketch of the region.
1 answer:
Answer:
Step-by-step explanation:
To find this probability, we shall be using the z-score route
Mathematically ;
z-score = (x -mean)/SD
From the question, x = 1.99, mean = 0 and SD = 1
So z = (1.99-0)/1 = 1.99
So the probability we want to calculate is;
P(z<1.99)
This value can be obtained from the standard normal distribution table.
P(z < 1.99) = 0.9767
The sketch of the region is as shown as in the attachment.
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Step-by-step explanation:
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1 = 1000
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<em><u>430 mL is the answer.</u></em>
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<em><u>Hope this helps</u></em>
Answer: 62
Step by step: sorry !!
Answer:
<h2>-223,948</h2>
Step-by-step explanation:
The formula of a sum of terms of a gometric sequence:
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3. Two widths are 36 cm.
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