H/6-1=-3 solve for H

Mathematics

1 answer:

tekilochka [14]3 years ago

5 0

Add 1 to both sides

h/6 = -3 + 1

Simplify -3 + 1 to -2

h/6 = -2

Multiply both sides by 6

h = -2 * 6

Simplify 2 * 6 to 12

h = -12

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77julia77 [94]

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nalin [4]

Here is your answer

B) 1/125

REASON:

Given,

$F (x)={(1/5)}^{x}$

for F (3)

Putting x=3, in above function we get

$F (3)= {(1/5)}^{3}= 1/125$

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What is the range of the function f(x) = 3x2 + 6x – 8?

timama [110]

Answer:

Range is {y | y ≥ –11}

Step-by-step explanation:

This is quadratic equation.

A quadratic equation's range can be found if we find the vertex.

For quadratic equations that have a positive number in front of $x^{2}$ , it is upward opening and thus all the numbers greater than or equal to the minimum value of vertex is the range.

The formula for vertex of a parabola is:

Vertex = $(-\frac{b}{2a}, f(-\frac{b}{2a})$

Where,

$a$ is the coefficient of $x^{2}$
$b$ is the coefficient of $x$

From our equation given, $a=3$ and $b=6$

Now, $x$ coordinate of vertex is $x=-\frac{b}{2a}\\x=-\frac{6}{(2)(3)}\\x=-\frac{6}{6}\\x=-1$

$y$ coordinate of the vertex IS THE MINIMUM VALUE that we want. We get this by plugging in the $x$ value [ $x=-1$ ] into the equation. So we have: