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Eduardwww [97]
3 years ago
10

What are the coordinates of the focus of the conic section shown below?

Mathematics
1 answer:
Aleksandr [31]3 years ago
7 0
The answer is 
y^2-4x+4y-4=y^2+4y-4x-4=(y+2)²-4x - 8= 0
it is the same of    x + 2 = (1/4 ) (y+2)²
   
the main formula is  x-h= a (y-k)² so h=-2, k= - 2 and a=1/4
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Can you find the distance between two points using absolute Value
Brut [27]

Answer:

no can not find the distance between two point using absolute value

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7 0
3 years ago
Identify the points corresponding to p and q. Help needed!!
givi [52]

Answer:

The points corresponding to P=(3,4) and Q=(6,7), so the answer is D.

Step-by-step explanation:

Ok, in mathematics, given two sets X and Y, the collection of all the ordered pairs (X, Y), formed with a first element in X and a second element in Y, is called the Cartesian product of X and Y. The Cartesian product of sets allows define relationships and functions. In this case, it is a function that contains two points, denoted P and Q. Given, the ordered pair of each, first read the one corresponding to the X axis  and then to the Y axis.

For P: you read X and you see that it is on 3 (between 2 and 4), and then the Y axis is on 4 (between 3 and 5).

For Q: you read X and you see that it is on 6 (between 5 and 7) and then the Y axis is on 7 (between 6 and 8)

8 0
2 years ago
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Snowcat [4.5K]
2h^3+h^2-8h=0 is in standard form
6 0
3 years ago
Simplifying rational expressions
Sonbull [250]
1. \frac{(c + 8)(c - 8)}{(c - 8)(c + 3)}_,_
    \frac{c + 8}{c + 3}_,_

2. \frac{n^{2} + 4n - 12}{n^{2} + 2n - 8}_,_
    \frac{n^{2} + 6n - 2n - 12}{n^{2} + 4n - 2n - 8}_,_
    \frac{n(n) + n(6) - 2(n) - 2(6)}{n(n) + n(4) - 2(n) - 2(4)}_,_
    \frac{n(n + 6) - 2(n + 6)}{n(n + 4) - 2(n + 4)}_,_
    \frac{(n - 2)(n + 6)}{(n - 2)(n + 4)}_,_
    \frac{n + 6}{n + 4}_,_

3. \frac{42x^{2}y^{3}}{28x^{3}y}_,_
    \frac{3y^{2}}{2x}_,_

4. \frac{m^{2} - 3m - 10}{m - 5}_,_
    \frac{m^{2} - 5m + 2m - 10}{m - 5}_,_
    \frac{m(m) - m(5) + 2(m) - 2(5)}{m - 5}_,_
    \frac{m(m - 5) + 2(m - 5)}{m - 5}_,_
    \frac{(m + 2)(m - 5)}{m - 5}_,_
    m + 2_,_
3 0
3 years ago
What is the center of the circle whose diameter has endpoints (18, -13) and (4, -3)?
jeka94

Answer:

Step-by-step explanation:

The center of the circle whose diameter has endpoints (18, -13) and (4, -3) will be the midpoint of the coordinates.

The ormua for calculating mid point is expressed as;

M(X,Y) ={(x21+x2/2, y1+y2/2}

X= x1+x2/2

Y = y1+y2/2

From the coordinates

x1 = 18 x2 = 4

X= 18+4/2

X = 22/2

X = 11

y1= -13, y2= -3

Y = -3-13/2

Y = -16/2

Y = -8

Hence the required centre will be at (11,-8)

4 0
3 years ago
Read 2 more answers
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