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Otrada [13]
3 years ago
14

PLZZZ HELP ME OUT THIS IS DUE TODAY!!!!

Mathematics
2 answers:
Yuri [45]3 years ago
5 0

Answer:

i gotchua

1. Negative , explanation: it is after the 0 line.

2. Negative, It is after the 0 line

3. Positive, It is before the 0 line

4. zero right on the 0 line.

5.zero right in the middle of the 0 line.

6.negative, a negative before the 0 line.

7.zero, a zero on the 0 line as well.

8. a positive as the o line and two numbers are together !

Hope this helped !! have a nice day !!! <3

svetlana [45]3 years ago
5 0
Damm I’m not even fat smart
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The equation of a circle is x^2+y^2-2x +6y-6=0. Find the center and radius of the circle by completing the square.you must inclu
zavuch27 [327]

Answer:

The center of the circle is at;

(1,-3)

The radius of the circle is;

r=4

Explanation:

Given the equation of circle;

x^2+y^2-2x+6y-6=0

we want to re-write it in the form;

(x-h)^2+(y-k)^2=r^2

where;

\begin{gathered} (h,k)\text{ is the center of the circle} \\ r\text{ is the radius} \end{gathered}

Applying Completing the square method;

\begin{gathered} x^2+y^2-2x+6y-6=0 \\ x^2-2x+1+y^2+6y+9=6+1+9 \\ (x-1)^2+(y+3)^2=16 \\ (x-1)^2+(y+3)^2=4^2 \end{gathered}

comparing the derived equation to the general form we have;

\begin{gathered} h=1 \\ k=-3 \\ r=4 \end{gathered}

Therefore;

The center of the circle is at;

(1,-3)

The radius of the circle is;

r=4

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Step-by-step explanation:

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