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dimulka [17.4K]
3 years ago
13

The system of linear equations -2x+y=8 and -3x-y=7 is graphed below. What is the solution to the system of equations? (–3, 2) (–

2, 3) (2, –3) (3, 2)
answer is
-3,2
Mathematics
2 answers:
Slav-nsk [51]3 years ago
8 0

Answer:

x = -3 , y = 2

Step-by-step explanation:

Solve the following system:

{y - 2 x = 8 | (equation 1)

{-3 x - y = 7 | (equation 2)

Swap equation 1 with equation 2:

{-(3 x) - y = 7 | (equation 1)

{-(2 x) + y = 8 | (equation 2)

Subtract 2/3 × (equation 1) from equation 2:

{-(3 x) - y = 7 | (equation 1)

{0 x+(5 y)/3 = 10/3 | (equation 2)

Multiply equation 2 by 3/5:

{-(3 x) - y = 7 | (equation 1)

{0 x+y = 2 | (equation 2)

Add equation 2 to equation 1:

{-(3 x)+0 y = 9 | (equation 1)

{0 x+y = 2 | (equation 2)

Divide equation 1 by -3:

{x+0 y = -3 | (equation 1)

{0 x+y = 2 | (equation 2)

Collect results:

Answer:  {x = -3 , y = 2

Strike441 [17]3 years ago
8 0

Answer:

Its -3,2 i just took the test :)

Step-by-step explanation:

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67.5675675676 rounded to the nearest tenth I get confused sometimes lol.....I completely forgot how this goes, please help me, i
dybincka [34]

Answer:

67.6

Step-by-step explanation:

Since 67.56 is 6 and above so, it is rounded to 6 so, it is 67.6.

4 0
3 years ago
Which expression below gives the average rate of change of the function g(x)= -x^2 -4x on the interval 6 ≤ x ≤ 8?
DiKsa [7]
The average rate of change of a function, g(x), over an interval [a, b] is given by 

Average\ rate\ of\ change= \frac{g(b)-g(a)}{b-a}

Thus, the average rate of change of g(x)=-x^2-4x over the interval 6\leq x\leq8 is given by:

Average\ rate\ of\ change= \frac{[-(8)^2-4(8)]-[-(6)^2-4(6)]}{8-6} \\  \\ = \frac{(-64-32)-(-36-24)}{2} = \frac{-96-(-60)}{2} = \frac{-96+60}{2} = \frac{-36}{2}  \\  \\ -18
6 0
3 years ago
Which of the following has no solution?
Sholpan [36]
The first one.
This statement is saying that x is less than zero and greater than zero at the same time. This is not possible. A number cannot be both negative and positive.
It's not the second one because this one includes equal to zero. It can be lass than or equal to zero and greater that or equal to zero because it can be ZERO.
It's not the third because this one is an OR statement. It can be less than or equal to zero OR greater than or equal to zero.
I hope you understand
8 0
3 years ago
Let f(x)=3x-8 and g(x)=x^2+4. <br> Find f(g(-2)).
9966 [12]

Answer:

  • 16

Step-by-step explanation:

<u>Given:</u>

  • f(x) =3x - 8 and g(x) = x² + 4
  • f(g(- 2)) = ?

<u>First find g(- 2):</u>

  • g(- 2) = (-2)² + 4 = 4 + 4 = 8

<u>Find f(8):</u>

  • f(8) = 3*8 - 8 = 24 - 8 = 16
8 0
2 years ago
Read 2 more answers
In 2000 the population of a country reached 1 ​billion, and in 2025 it is projected to be 1.2 billion. ​(a) Find values for C an
Mice21 [21]

Answer:

(a) The value of C is 1.

(b) In 2010, the population would be 1.07555 billions.

(c) In 2047, the population would be 1.4 billions.

Step-by-step explanation:

(a) Here, the given function that shows the population(in billions) of the country in year x,

P(x)=Ca^{x-2000}

So, the population in 2000,

P(2000)=Ca^{2000-2000}

=Ca^{0}

=C

According to the question,

P(2000)=1

\implies C=1

(b) Similarly,

The population in 2025,

P(2025)=Ca^{2025-2000}

=Ca^{25}

=a^{25}                    (∵ C = 1)

Again according to the question,

P(2025)=1.2

a^{25}=1.2

Taking ln both sides,

\ln a^{25}=\ln 1.2

25\ln a = \ln 1.2

\ln a = \frac{\ln 1.2}{25}\approx 0.00729

a=e^{0.00729}=1.00731

Thus, the function that shows the population in year x,

P(x)=(1.00731)^{x-2000}     ...... (1)

The population in 2010,

P(2010)=(1.00731)^{2010-2000}=(1.00731)^{10}=1.07555          

Hence, the population in 2010 would be 1.07555 billions.

(c) If population P(x) = 1.4 billion,

Then, from equation (1),

1.4=(1.00731)^{x-2000}

\ln 1.4=(x-2000)\ln 1.00731

0.33647 = (x-2000)0.00728

0.33647 = 0.00728x-14.56682

0.33647 + 14.56682 = 0.00728x

14.90329 = 0.00728x

\implies x=\frac{14.90329}{0.00728}\approx 2047

Therefore, the country's population might reach 1.4 billion in 2047.

3 0
3 years ago
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