Let x = speed of the first car
the second car is 12 km slower so the seconds car speed is x-12
they each drove 2 hours so 1st car = 2x
2nd car = 2(x-12)
they drove 360 km
so you have 2x + 2(x-12) = 360
solve for x
2x+2(x-12) = 360
2x + 2x-24 = 360
4x-24 = 360
4x = 384
x = 384/4
x = 96
1st car drove at 96 km per hour
slower car drove at 96-12 = 84 km per hour
Answer:
a. x = 5/2
b. y = 16.5
c. z = 12
Step-by-step explanation:
The order of the numbers for a 6-digit number from left to right is as follows:
hundred thousands, ten thousands, thousands, hundreds, tens and then units
We want two numbers were the greater number is determined by its hundreds place, these two numbers can be:
165,827 and 165,229
The hundreds in the first is 8 while the hundreds in the second is 2. Therefore, the first number is larger.
