Answer:
For question a, it simplifies. If you re-express it in boolean algebra, you get:
(a + b) + (!a + b)
= a + !a + b
= b
So you can simplify that circuit to just:
x = 1 if b = 1
(edit: or rather, x = b)
For question b, let's try it:
(!a!b)(!b + c)
= !a!b + !a!bc
= !a!b(1 + c)
= !a!b
So that one can be simplified to
a = 0 and b = 0
I have no good means of drawing them here, but hopefully the simplification helped!
Answer:
Secure is the correct answer for the above question.
Explanation:
- When any person wants that any information is not hacked by any user then he needs to secure the information with the help of any security mechanism. This security mechanism can be of any type that facilities the user to stop the information are being hacked.
- The above question asked about the work which is needed to stop the message is being hacked. So there is a need to secure the information. so secure is the correct option while the other option is not valid because "simple, economical or verifiable" can not stop the message from accessed by the unauthorized user.
It says you’ve only answered 11, but yeah it you’re account CAN be hacked
Answer:
Link Aggregation Control Protocol
Explanation:
Link Aggregation Control Protocol can be used to assist in the formation of port channel bundles of physical links.
Link Aggregation Control Protocol is an IEEE standard defined in IEEE 802.3ad. LACP lets devices send Link Aggregation Control Protocol Data Units (LACPDUs) to each other to establish a link aggregation connection.
#include<stdio.h>
#include<stdlib.h>
int comment1(FILE *fp)
{
char ch;
int count=0;
while(fscanf(fp,"%c",&ch)!=EOF)
{
if(ch=='\n')
{
return count;
}
count++;
}
return count;
}
int comment2(FILE *fp)
{
char ch;
int count=0;
while(fscanf(fp,"%c",&ch)!=EOF)
{
if(ch=='*')
{
fscanf(fp,"%c",&ch);
if(ch=='/')
{
return count;
}
count++;
}
count++;
}
return 0;
}
int main()
{
printf("Enter the file name:");
char s[1000],ch,ch1;
scanf("%s",s);
FILE*fp;
fp = fopen(s,"r");
int count=0;
while(fscanf(fp,"%c",&ch)!=EOF)
{
if(ch=='\"')
{
while(fscanf(fp,"%c",&ch)!=EOF)
{
if(ch=='\"')
{
break;
}
if(ch=='\\')
{
fscanf(fp,"%c",&ch);
}
}
}
else if(ch=='/')
{
fscanf(fp,"%c",&ch);
if(ch=='/')
{
count += comment1(fp);
}
else if(ch=='*')
{
count += comment2(fp);
}
}
}
printf("%d\n",count);
return 0;
}
