Answer:
Software Package means software which is used collectively, implements alike purposes, or combines alike characteristics and is bundled collectively being one kit from software applications, where as, Integrated software is a combination of software specifically built to operate on almost linked applications.
Explanation:
Users should choose Software Package because of the following reasons:
Cheap price compared over buying individual application independently.
Opportunity to introduce the total of the applications at the corresponding period or just that applications you require to work.
The compatible user interface of individual application over another.
The facility to distribute data among applications.
Coming updates can refresh every application whole by the corresponding event.
Perfect for individual use, licensed use, huge or little company.
Every software holds the full-featured transcription.
Yes because the UV light is brighter
In this program, I am using the school-based grading system and the program should accept the subject and the number of students.
Program approach:-
- Using the necessary header file.
- Using the standard I/O namespace function.
- Define the main function.
- Declare the variable.
- Display enter obtain marks in 5 subjects.
- Return the value.
Program:-
//header file
#include<iostream>
//using namespace
using namespace std;
//main method
int main()
{
//declare variable
int j;
float mark, sum=0, a;
//display enter obtain marks in 5 subjects
cout<<"Enter Marks obtained in 5 Subjects: ";
for(j=0; j<5; j++)
{
cin>>mark;
sum = sum+mark;
}
a = sum/5;
//display grade
cout<<"\nGrade = ";
if(a>=91 && a<=100)
//display a1
cout<<"a1";
else if(a>=81 && a<91)
//display a2
cout<<"a2";
else if(a>=71 && a<81)
cout<<"b1";
else if(a>=61 && a<71)
cout<<"b2";
else if(a>=51 && a<61)
//display c1
cout<<"c1";
else if(a>=41 && a<51)
//display c2
cout<<"c2";
else if(a>=33 && a<41)
//display d
cout<<"d";
else if(a>=21 && a<33)
//display e1
cout<<"e1";
else if(a>=0 && a<21)
//display e2
cout<<"e2";
else
//display invalid
cout<<"Invalid!";
cout<<endl;
//return the value
return 0;
}
Learn more grading system
brainly.com/question/24298916
Answer:
60 J
Explanation:
Given,
Work done to push the box = 100 J
Energy dissipated by friction = 40 J.
According to work energy theorem work done is equal to change in kinetic energy.
Change in Kinetic energy = Work done by student + Work done by friction
Change in Kinetic energy = 100 J - 40 J
Work done by the friction will be negative because it will act in opposite direction of force applied.
Change in Kinetic energy = 60 J