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notka56 [123]
3 years ago
6

What is the greatest common factor of 42,28 and 70?

Mathematics
2 answers:
eduard3 years ago
7 0

Answer:

the greatest common factor would be 14 . Hope this helped

Step-by-step explanation:

padilas [110]3 years ago
6 0
THE ANSWER IS 14!!!!
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If a escape room party has 16 participants and 4 escape puzzles.How many staff are needed?
bija089 [108]

Answer:

4

Step-by-step explanation:

if there are 4 puzzles and only 16 participants. Also WHAT??? makes no since what to do

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Murrr4er [49]

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34 students per teacher.

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Y=x.arctan(x)^1/2. find dy/dx. pls show steps​
Whitepunk [10]

y=x(\arctan x)^{1/2}

Use the product rule first:

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dx}{\mathrm dx}(\arctan x)^{1/2}+x\dfrac{\mathrm d(\arctan x)^{1/2}}{\mathrm dx}

\dfrac{\mathrm dy}{\mathrm dx}=(\arctan x)^{1/2}+x\dfrac{\mathrm d(\arctan x)^{1/2}}{\mathrm dx}

Use the chain rule to compute the derivative of (\arctan x)^{1/2}. Let z=(\arctan x)^{1/2} and take u=\arctan x, so that by the chain rule

\dfrac{\mathrm dz}{\mathrm dx}=\dfrac{\mathrm dz}{\mathrm du}\dfrac{\mathrm du}{\mathrm dx}

\dfrac{\mathrm dz}{\mathrm du}=\dfrac{\mathrm du^{1/2}}{\mathrm du}=\dfrac12u^{-1/2}

\dfrac{\mathrm du}{\mathrm dx}=\dfrac{\mathrm d\arctan x}{\mathrm dx}=\dfrac1{1+x^2}

\implies\dfrac{\mathrm d(\arctan x)^{1/2}}{\mathrm dx}=\dfrac1{2(\arctan x)^{1/2}(1+x^2)}

So we have

\dfrac{\mathrm dy}{\mathrm dx}=(\arctan x)^{1/2}+\dfrac x{2(\arctan x)^{1/2}(1+x^2)}

You can rewrite this a bit by factoring (\arctan x)^{-1/2}, just to make it look neater:

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac1{2(\arctan x)^{1/2}}\left(2\arctan x+\dfrac x{1+x^2}\right)

3 0
3 years ago
PLS HELP ILL GIVE BRAINLIEST!
Vlad1618 [11]

Answer:

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Step-by-step explanation:

If x = -4, we would use the expression of the limit "if x is less than or equal to -1" since x is just that.

We would then plug in our x value into the expression and solve for g(x)

g(x) = -x + 4 -->  -(-4) + 4 = 4 + 4 = 8

7 0
3 years ago
Escape velocity is a measure of how fast an object must be moving to escape the
joja [24]

Answer:

The object has to be moving

miles per hour to escape the moon's gravity.

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3 years ago
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