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Arada [10]
3 years ago
12

On an airplane, there are two seats on the left side in each row and three seats on the right side. There are 90 seats on the ri

ght side of the plane
Mathematics
2 answers:
Margarita [4]3 years ago
8 0

Answer:

the answer is below :)

Step-by-step explanation:

since there are 90 seats on the right side and there are 3 seats in each row you are going to dive 90 seats by 3 seats which gives you 30 rows

now since there are 30 rows your going to multiply 30 rows by the number of seat on the left side which is 2. So 30 times 2 is 60


vladimir2022 [97]3 years ago
4 0

you would need to divide 90 by 3 because that is how many there are in each row.

you will get 30

then you need to multiply 30 by 2 becanse that is how many are in the rows on the left.

you will get 60,

so there are 60 seats on the left.

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Jim leaves the gym running 5 mph. Ten minutes later Bob leaves the gym on his bike traveling at a speed of 8 mph. how long will
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26 2/3 minutes:  The two boys meet after 26 2/3 minutes

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Distance covered by Jim = Distance covered by Bob

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Simplify this by performing the indicated multiplication:

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The distribution of resistance for resistors of a certain type is known to be normal, with 10% of all resistors having a resista
baherus [9]

Answer:

The mean is 9.65 ohms and the standard deviation is 0.2742 ohms.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

10% of all resistors having a resistance exceeding 10.634 ohms

This means that when X = 10.634, Z has a pvalue of 1-0.1 = 0.9. So when X = 10.634, Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{10.634 - \mu}{\sigma}

10.634 - \mu = 1.28\sigma

\mu = 10.634 - 1.28\sigma

5% having a resistance smaller than 9.7565 ohms.

This means that when X = 9.7565, Z has a pvalue of 0.05. So when X = 9.7565, Z = -1.96.

Z = \frac{X - \mu}{\sigma}

-1.96 = \frac{9.7565 - \mu}{\sigma}

9.7565 - \mu = -1.96\sigma

\mu = 9.7565 + 1.96\sigma

We also have that:

\mu = 10.634 - 1.28\sigma

So

10.634 - 1.28\sigma = 9.7565 + 1.96\sigma

1.96\sigma + 1.28\sigma = 10.645 - 9.7565

3.24\sigma = 0.8885

\sigma = \frac{0.8885}{3.24}

\sigma = 0.2742

The mean is

\mu = 10.634 - 1.28\sigma = 10 - 1.28*0.2742 = 9.65

The mean is 9.65 ohms and the standard deviation is 0.2742 ohms.

8 0
3 years ago
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