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2 years ago

The equation for the circle below is x^2+y^2=64 what is the length of the circle’s radius

Mathematics

1 answer:

FromTheMoon [43]2 years ago

3 0

Answer:

Step-by-step explanation:

The standard form of an equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the equation:

$x^2+y^2=64\\\\(x-0)^2+(y-0)^2=8^2$

Therefore the center is (0, 0) and the radius r = 8

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Round 82.265 to the nearest whole number.

Zinaida [17]

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3 years ago

A) 5.(-3).(-4) =

Fofino [41]

A) 5×(-3)×(-4)=60
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3 years ago

Solve 3x2−3x=0 by factoring.

o-na [289]

Answer:

3x(x-1) = 0

x= 1

Step-by-step explanation:

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5 0

3 years ago

**Solve by Elimination<br> 3 + 2x - y = 0<br> -3-7y = 10x<br> 7) x =<br> 8) y =

timofeeve [1]

Answer:

Explanation:

3 + 2x - y = 0
Or 2x - y = -3 (1)

-3-7y = 10x
Or -10x - 7y = 3 (2)

2x - y = -3 (1)
-10x - 7y = 3 (2)
———————

Multiply 5 to (1)

5(2x - y = -3)
-10x - 7y = 3
———————
10x - 5y = -15
-10x - 7y = 3
———————
-12y = -12
y = -12/-12
y = 1

Plug y value in (1)

2x - 1 = -3
2x = -3 + 1
2x = -2
x = -2/2 = -1

Therefore, x = -1 and y = 1

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2 years ago

Given 3x^2+x-4/x-1 what are the domain and range

Katarina [22]

Answer:

doman: x ≠ 1
range: y ≠ 7

Step-by-step explanation:

The domain is the horizontal extent of the graph, the set of x-values for which the function is defined. The range is the vertical extent of the graph, the set of y-values defined by the function.

<h3>Simplified</h3>

The given function is undefined where its denominator is zero, at x=1. Everywhere else, it can be simplified to ...

$\dfrac{3x^2+x-4}{x-1}=\dfrac{(x-1)(3x+4)}{(x-1)}=3x+4\quad x\ne 1$

<h3>Domain</h3>

The simplified function (3x+4) is defined for all values of x except x=1. The simplest description is ...

x ≠ 1

In interval notation, this is ...

(-∞, 1) ∪ (1, ∞)

<h3>Range</h3>

The simplified function is capable of producing all values of y except the one corresponding to x=1: 3(1)+4 = 7. The simplest description is ...

y ≠ 7

In interval notation, this is ...

(-∞, 7) ∪ (7, ∞)

6 0

1 year ago