02-3+30-8+p+p

Mathematics

1 answer:

kupik [55]3 years ago

4 0

The constants, -3 and -8, are like terms

The terms 3p and p are like terms

The terms in the expression are p^2, -3, 3p, -8, p, p^3

The expression contains 6 terms.

Like terms have the same variables raised to the same powers.

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Step-by-step explanation:

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WILL MARK BRAINLIEST FOR THE BEST ANSWER. PLEASE SHOW FULL SOLUTIONS. THANK YOU AND GOD BLESS. THE QUESTION IS ATTACHED. :)

Anuta_ua [19.1K]

9514 1404 393

Answer:

(x, y) = (34/5, -4/5) = (6.8, -0.8)

Step-by-step explanation:

Subtract the first equation from the second to eliminate x.

$\left(\dfrac{x}{3}-\dfrac{y}{2}\right)-\left(\dfrac{x-5}{3}+\dfrac{y+2}{3}\right)=\left(\dfrac{8}{3}\right)-(1)\\\\y\left(-\dfrac{1}{2}-\dfrac{1}{3}\right)+\left(\dfrac{5}{3}-\dfrac{2}{3}\right)=\dfrac{5}{3} \qquad\text{partially simplify}\\\\-\dfrac{5}{6}y=\dfrac{2}{3} \qquad\text{subtract 1}\\\\y=-\dfrac{4}{5} \qquad\text{multiply by $-\dfrac{6}{5}$}$

Substituting for y in the second equation, we can find x.

$\dfrac{x}{3}-\dfrac{1}{2}\left(-\dfrac{4}{5}\right)=\dfrac{8}{3}\\\\5x +6=40 \qquad\text{multiply by 15}\\\\5x=34\qquad\text{subtract 6}\\\\x=\dfrac{34}{5}$