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devlian [24]
3 years ago
6

-6x + 7x + 14 = 3Drag and drop the reasons into the boxes to correctly complete the tables.​

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
5 0

Answer:

Dude just drag it into the box

Step-by-step explanation:

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H < 1 I think that's the answer
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Solve.<br> 7n - 5 &gt; -2n + 4
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A sequence is defined recursively by the formula F (n+1)=-2f(n). The 1st term of the sequence is -1.5. What is the next term in
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F(2)=3

Step-by-step explanation:

The first term is -1.5= f(1).

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If sin theta = 8/17 and cot theta &lt; 0, what is sec theta?
klasskru [66]

Answer:

-\frac{17}{15}

Step-by-step explanation:

By definition, \cot \theta=\frac{1}{\tan \theta} and \sec \theta=\frac{1}{\cos \theta}. Since since \cot \theta is negative, \tan \theta must also be negative, and since \sin \theta is positive, we must be in Quadrant II.

In a right triangle, the sine of an angle is equal to its opposite side divided by the hypotenuse. The cosine of an angle in a right triangle is equal to its adjacent side divided by the hypotenuse. Therefore, we can draw a right triangle in Quadrant II, where the opposite side to angle theta is 8 and the hypotenuse of the triangle is 17.

To find the remaining leg, use to the Pythagorean Theorem, where a^2+b^2=c^2, where c is the hypotenuse, or longest side, of the right triangle and a and b are the two legs of the right triangle.

Solving, we get:

8^2+b^2=17^2,\\b^2=17^2-8^2,\\b^2=\sqrt{17^2-8^2}=\sqrt{225}=15

Since all values of cosine theta are negative in Quadrant II, all values of secant theta must also be negative in Quadrant II.

Thus, we have:

\sec\theta=\frac{1}{\cos \theta}=-\frac{1}{\frac{15}{17}}=\boxed{-\frac{17}{15}}

6 0
3 years ago
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