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4 years ago

A line has a y-intercept of 4 and a slope of 7. What is its equation in slope-intercept form?

Mathematics

1 answer:

gladu [14]4 years ago

4 0

Answer:

y=7x+4

Step-by-step explanation:

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Evalute 10(4+3*2)/(2*6-7) <br> [2.3,2.5,2.7,2.9,3.1]

Olenka [21]

"evaluate 10(4+3*2)/(2*6-7)

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3 years ago

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3 years ago

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Margarita [4]

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3 years ago

Read 2 more answers

I seriously need help.

Leni [432]

Let's go:

y = ax + b

{5 = 4a + b

{15 = - 6a + b

{5 = 4a + b

{- 15 = 6a - b

10a = - 10

a = - 1

5 = 4a + b

4.(-1) + b = 5

b - 4 = 5

b = 9

- 1; 9

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I hope I helped you.

3 0

3 years ago

Assume that x equals x (t )and y equals y (t ). Let y equals x cubed plus 4 and StartFraction dx Over dt EndFraction =2 when xe

nika2105 [10]

Answer:dy/dt(x=3)=54

Step-by-step explanation:

We know that we can write:

$\frac{dy}{dt}=\frac{dy}{dx} *\frac{dx}{dt}$

and so evaluate it as a product of functions, that is for a given value of x or t, we get that

$\frac{dy}{dt}(s)=\frac{dy}{dx} (s) * \frac{dx}{dt}(s)$ .

Now we are told that:

$1. x=x(t),\ 2.y=x^3+4,\ \frac{dx}{dt} =2,\ for \ x=3,$

whenever it happens, this means the influence of t is hidden, and we only consider the result, that is, how much is x when the derivative has the value of 2, we are not concerned for what value of t it happens, since we get all the necessary information beforehand.

Now we need to calculate

$\frac{dy}{dx}=3x^2 \rightarrow \frac{dy}{dx}(3)=3(3)^2=27$ .

Therefore

$\frac{dy}{dt}(x=3)=\frac{dy}{dx} (x=3) * \frac{dx}{dt}(x=3)$ or

$\frac{dy}{dt}(x=3)=27 *2 = 54$ .

7 0

4 years ago