Answer:
y = x - 6
Step-by-step explanation:
The slope of y = -x is -1, so the slope of any line perpendicular to y = -x is +1. Thus,
y = mx + b becomes 2 = 1(8) + b, so that b = -6.
The desired equation is y = x - 6.
Check: Does (8,2) lie on this line? Is 2 = 8 - 6 true? YES.
<span>6b^3 (2a+7b)
</span>
<span><span>(<span>6b^3</span>)</span><span>(<span>2a+7b</span><span>)
</span></span></span>
<span><span><span>=(<span>6b^3</span>)</span><span>(2a)</span></span>+<span><span>(<span>6b^3</span>)</span><span>(7b)
</span></span></span>
<span><span>=12ab^3</span>+<span>42<span>b^4]
Answer: </span></span></span>
<span><span><span>12a</span><span>b^3</span></span>+<span>42<span>b^4</span></span></span>
0.5 as a decimal
hope this partially helped:)
sorry couldn't answer completely
let me know if it helped a bit:)
Start from the parent function 
In the first case, you are computing
In the second case, you are computing
![f(x+1)-2 /tex] There are two translation going on: when you transform [tex] f(x) \to f(x+k)](https://tex.z-dn.net/?f=%20f%28x%2B1%29-2%20%2Ftex%5D%3C%2Fp%3E%20%3Cp%3EThere%20are%20two%20translation%20going%20on%3A%20when%20you%20transform%20%5Btex%5D%20f%28x%29%20%5Cto%20f%28x%2Bk%29%20)
, you translate the function horizontally, 
units left if 
and units right if 
.
On the other hand, when you transform 
, you translate the function vertically, units up if and units down if .
So, the first function is the "original" parabola , translated 
units right and 
units up. Likewise, the second function is the "original" parabola , translated 
units left and 
units down.
So, the transformation from 
to 
is: go 
units to the left and units down
