This may be the correct answer but I am not sure
If I'm understanding the question correctly, this is how I would estimate the sum.
I would round each number to the nearest tens place.
33 would be rounded down to 30.
89 would be rounded up to 90.
Then I would do 90+30.
Answer:
<u>V = 5,324 in^3</u>
Step-by-step explanation:
V = 4(
r^3)/3
= 4(3)(11^3)/3
= 12(11)(11)(11)/3
= 12(1,331)/3
= 15,972/3
<em><u>V = 5,324 in^3</u></em>
(x,y) or
(x,f(x))
so just plug the first value in and see if yo get the 2nd value
A. when x=-2, then is f(x)=48?
remember, x^-m=1/(x^m)
3(1/4)^-2=3/((1/4)^2)=3/(1/16)=3*16=48
true
B. x^0=1
so 3(1/4)^0=3(1)=3
true
C. when x=2
3(1/4)^2, 3(1/16), 3/16
true
D. 12
das is obviously false but anyway
3(1/4)^12=3(1/big number)=3/big number=small number but not zero
answer is A,B,C
Since the shape is a square the sides are equal. Then we need to find x such that x * x = 169.
Sqrt(169) = 13
So x = 13
