Answer: 50.27
Step-by-step explanation:
Area = pi r^2
= pi x 16
use the number it and equation it with number and new number will form
Oh Foxy, Foxy, how totally debilitated you must be ! Try to relax. Nobody
enjoys a painful brain, and believe me, this problem is not worth it.
Let me put it to you this way: What if the problem said . . .
-- Demarcus has $8 more than his sister.
-- His sister has $4.
-- How much money ' M ' does Demarcus have ?
If your brain didn't hurt, you could quickly solve this right in there.
You would know that Demarcus' money ' M ' = 8 + 4 .
That's <em>almost </em>exactly what the problem <em>does</em> say.
Except it doesn't say he has "$8 more than his sister",
it says he has "at least" that much.
So you know that ' M ' is not exactly = 8 + 4, but that's the <u>least</u> it could be.
The actual amount of ' M ' is <u>more</u> than that.
Surely you can handle it from here, even with half of your brain
tied behind your back.
Take a good hard look at ' A ', and then go lie down.
Answer:
8 forks for every 1 table I hope this helped u :))
Step-by-step explanation:
![\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad radius=\stackrel{}{ r}\\\\ -------------------------------\\\\ (x-3)^2+(y+7)^2=64\implies [x-\stackrel{h}{3}]^2+[y-(\stackrel{k}{-7})]^2=\stackrel{r}{8^2} \\\\\\ center~(3,-7)\qquad radius=8](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bequation%20of%20a%20circle%7D%5C%5C%5C%5C%20%0A%28x-%20h%29%5E2%2B%28y-%20k%29%5E2%3D%20r%5E2%0A%5Cqquad%20%0Acenter~~%28%5Cstackrel%7B%7D%7B%20h%7D%2C%5Cstackrel%7B%7D%7B%20k%7D%29%5Cqquad%20%5Cqquad%20%0Aradius%3D%5Cstackrel%7B%7D%7B%20r%7D%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C%0A%28x-3%29%5E2%2B%28y%2B7%29%5E2%3D64%5Cimplies%20%5Bx-%5Cstackrel%7Bh%7D%7B3%7D%5D%5E2%2B%5By-%28%5Cstackrel%7Bk%7D%7B-7%7D%29%5D%5E2%3D%5Cstackrel%7Br%7D%7B8%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0Acenter~%283%2C-7%29%5Cqquad%20radius%3D8)
so, the broadcast location and range is more or less like the picture below.
