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kari74 [83]
3 years ago
13

Use the slope formula to find the slope of the line passing through the given points.

Mathematics
2 answers:
solong [7]3 years ago
6 0
The answer you are looking for is -1/3 or -3

Zanzabum3 years ago
5 0
-1/3. Use the formula x1-x2/y1-y2
You might be interested in
Simplify the following
yarga [219]
The answer is actually c. u just multiply 5 and 4n which gives u 20n. and then u multiply 5 and -13 which equals -65.
8 0
3 years ago
I really need help >_< please and thank you
SashulF [63]
So for each of the graphs, you basically just have to fill out slope form, which is y=my+b. And to make this equation, you need to find each variable.

First, find the slope. To calculate slope, count the rise (how many units up or down) the line goes from any point to the next immediate point, then the run (how many units left or right.) This should leave you with a fraction, rise/run. For example, on number 3, from labeled points (-5, -4) to (5,2) (double check cause it’s hard to see on my phone, but i think those are the points on 1??) it rises 6 units (-4 to 2) and runs 10 units (-5 to 5). This gives you your rise/run fraction, which is 6/10, simplified to 3/5.

So the slope fills out the m part of the equation. For 3, we found that slope is 3/5, and that fits into the m variable of the slope equation.

This makes it y=3/5x+b.

The last (and considerably less confusing) step is to find b. b is the y-intercept, which is just the point in the graph where the line crosses the y-axis and x=0. On 3, this would be (0,-1) or just -1.

So fill -1 into the b slot of the equation, and you get y=3/5x-1. And thats it!!

Let me know if you still need help on any of the other problems, but I hoped this helped to clear it up!! :)


8 0
4 years ago
Writing y = mx + b given a Graph
mart [117]

Answer:

  • y = 1

Step-by-step explanation:

First, we need to find the y-intercept. The y-intercept is the intersection of the point on the y-axis. We can clearly tell that the y-intercept is 1. The slope is definitely 0 because it shows a straight line.

Hence, the equation is y = 1.

Please check out my graph to support my reasoning.

7 0
3 years ago
An object is launched from ground level with an initial velocity of 120 meters per second. For how long is the object at or abov
babunello [35]

Answer:

D) 14 seconds

Step-by-step explanation:

First we will plug 500 in for y:

500 = -4.9t² + 120t

We want to set this equal to 0 in order to solve it; to do this, subtract 500 from each side:

500-500 = -4.9t² + 120t - 500

0 = -4.9t²+120t-500

Our values for a, b and c are:

a = -4.9; b = 120; c = -500

We will use the quadratic formula to solve this.  This will give us the two times that the object is at exactly 500 meters.  The difference between these two times will tell us when the object is at or above 500 meters.

The quadratic formula is:

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Using our values for a, b and c,

x=\frac{-120\pm \sqrt{120^2-4(-4.9)(-500)}}{2(-4.9)}\\\\=\frac{-120\pm \sqrt{14400-9800}}{-9.8}\\\\=\frac{-120\pm \sqrt{4600}}{-9.8}\\\\=\frac{-120\pm 67.8233}{-9.8}\\\\=\frac{-120+67.8233}{-9.8}\text{ or }\frac{-120-67.8233}{-9.8}\\\\=\frac{-57.1767}{-9.8}\text{ or }\frac{-187.8233}{-9.8}\\\\=5.3242\text{ or }19.1656

The two times the object is at exactly 500 meters above the ground are at 5 seconds and 19 seconds.  This means the amount of time it is at or above 500 meters is

19-5 = 14 seconds.

6 0
3 years ago
Marcus states that the polynomial expression 3x3 – 4x2y + y2 + 2 is in standard form. Ariel states that it should be y2 – 4x2y +
lubasha [3.4K]
The degree of a polynomial is the highest power of its terms.
The power of a term is the sum of the powers of all the variables in a term.
A polynomial is written starting with the greatest power in standard form.
In the first case, the power of the first term is 3, the power of the second is 3 (2 from x + 1 from y) but the power of x has decreased so it is the second term, and then so on. 
In the second case, the power is starting form 2 and then increasing to 3. This is incorrect.
Therefore, Marcus' suggestion is correct.
4 0
3 years ago
Read 2 more answers
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