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makkiz [27]
3 years ago
12

Does ripping a dvd erase the original content

Computers and Technology
1 answer:
kap26 [50]3 years ago
7 0
No, ripping is the process of reading all content in order to make a copy. Nothing is erased.
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Since all Java data types (numbers, strings, etc) can be represented as strings, the _______ format specifier can receive any ty
astra-53 [7]

In Java programming, the <u>%s</u> format specifier can receive any type of Java data.

<h3>The kinds of data type.</h3>

In Computer programming, there are five recognized data types and these include:

  • Integer type (int).
  • Character type (char).
  • Floating point type (float).
  • Boolean (bool)
  • String (str)

<h3>What is a string?</h3>

A string is a data type which is typically used for data values that comprises ordered sequences of characters.

In Java programming, strings can be used to represent all Java data types such as numbers, Boolean, strings, etc. Also, the <u>%s</u> format specifier can be used by a programmer or software developer to receive any type of Java data.

Read more on a string here: brainly.com/question/25619349

5 0
2 years ago
Write a program in C++ to implement bubblesort using the swap function ?
marishachu [46]

C++ program for implementation of Bubble sort  

#include <bits/stdc++.h>  

using namespace std;  

 void swap(int *x, int *y)  /*Defining Swap function of void return type*/

{  

  int temp = *x;  //Swaping the values  

   *x = *y;  

   *y = temp;  

}  

void bubbleSort(int array[], int n) /*Defining function to implement bubbleSort  */

{  

  int i, j;  

  for (i = 0; i < n-1; i++)      

      for (j = 0; j < n-i-1; j++)  /*The last i components are already in location  */

      if (array[j] > array[j+1])  

          swap(&array[j], &array[j+1]);  //Calling swap function

}  

int main()  //driver function

{  

   int array[] = {3, 16, 7, 2, 56, 67, 8}; //Input array  

   int n = sizeof(array)/sizeof(array[0]);  //Finding size of array

   bubbleSort(array, n); //Function calling  

   cout<<"Sorted array: \n";  

   for (int i = 0; i < n; i++)  //printing the sorted array

       cout << array[i] << " ";  

   cout << endl;  

 return 0;  

}  

<u>Output</u>

Sorted array:  

2 3 7 8 16 56 67

3 0
3 years ago
Which of the following technologies is the best choice to convey urgent and highly sensitive information? telephone fax letter e
snow_lady [41]
Using e-mail to send messages is the best choice to convey urgent and highly sensitive information. E-mail is just a conversation between you and the recipient. So it is the best when it comes to when you are sending a highly sensitive information. While telephone fax letter and dispatch radio may need to use a mediator to transfer messages which violates the confidentiality of the information.
3 0
3 years ago
You started using a new Windows server three months ago. Since that time, you have found that the system slows down and crashes
Brut [27]

Answer: Open Reliability Monitor.

Explanation:

The simplest way to view this information is to open the reliability monitor.

The Reliability Monitor shows you the stability history of a system at a glance and also allows one to see the details of the events that has an effect on reliability on a daily basis.

The reliability and problem history chart which can be seen in the Reliability Monitor helps in keeping track of the overall health of the server on a daily basis.

4 0
2 years ago
Which of these is NOT a cloud-based system?
-BARSIC- [3]
Skype isn't a cloud based system. Cloud based systems are online storage systems. Google Drive, Dropbox, and SkyDrive are all pieces of software which allow you to store data on a remote server over the internet. Skype is just a program.
7 0
3 years ago
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