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3 years ago

Johns weight exceeds 100 lbs. by x. Johns weight would be represented my

Mathematics

2 answers:

yanalaym [24]3 years ago

6 0

The answer is A because x is added so 100+x is correct

Alexxandr [17]3 years ago

5 0

Uhm, I think its A. Good luck!

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Gerald works at a warehouse that ships products to various grocery stores. He has 230 boxes of oatmeal to ship. If Gerald can pl

never [62]

Answer:

Step-by-step explanation:

He only can put 12 boxes in 1 crate to ship 230 boxes of oatmeal the least number of crates he can use is 20 because 20 crates would= up to 240 boxes.

He can't do 19 boxes because he is short he would then only have 228 boxes and that is 2 short.

But if he does 20 crates he would be good for what needs and just have 10 more extra.

My calculations.

2 0

1 2

____

4 0

2 0 0

_________

2 4 0

This is saying he had 20 crates and use x as number of boxes for example each 1 crate could ship x amount of boxes and x is representing 12 boxes per crate and since he has 20 crates what is 20 x 12= x( the number of boxes total(240 boxes)

I hope this helps have a awesome day:)

6 0

2 years ago

Read 2 more answers

PLEASE HELP ME WITH THESE ASAP <br> i'll give brainlist

ValentinkaMS [17]

Answer:

5/288

Step-by-step explanation:

7 0

3 years ago

Sophia has an ear infection. The doctor prescribes a course of antibiotics. Sophia is told to take 500 mg doses of the antibioti

Y_Kistochka [10]

Answer:

<h3>After 1st Dose:</h3>

As Sophie has just taken the medicine, the quantity of drug present in her body is 500mg

<h3>After 2nd Dose:</h3>

Amount left from 1st dose = 4.5/100 × 500 = 22.5mg

Amount of Drug after 2nd dose = Amount left from 1st dose + 2nd dose taken.

Amount of Drug after 2nd dose = 22.5mg + 500mg

Amount of Drug after 2nd dose = 522.5mg

<h3>After 3rd Dose:</h3>

Amount left from 2nd dose = 4.5/100 × 522.5 = 23.513 mg

Amount of Drug after 3rd dose = Amount left from 2nd dose + 3rd dose taken.

Amount of Drug after 3rd dose = 23.513mg + 500mg

Amount of Drug after 3rd dose = 523.513 mg

<h3>After 4rth Dose:</h3>

Amount left from 3rd dose = 4.5/100 × 523.513 = 23.558mg

Amount of Drug after 4rth dose = Amount left from 3rd dose + 4rth dose taken.

Amount of Drug after 4rth dose = 23.558mg + 500mg

Amount of Drug after 4rth dose = 523.558 mg

<h3>Highest Amount:</h3>

The pattern formed above can be written in the form of sum of finite geometric series:

Sₙ = 500 + 500(0.045) +500(0.045)² + ........................500(0.045)ⁿ

Sₙ = 500(1 + 0.045 + 0.045² ........................0.045ⁿ)

Where

Sₙ = Sum till nth term

a = 500

r = 0.045

As Sophia takes medicines 2 times a day, she takes medicine 20 times in 10 days. So substitute n=20 in the formula for the sum of finite geometric series

$S_n=a\frac{(1-r^n)}{1-r}\\S_{20}=500(\frac{1-0.045^{20}}{1-0.045})\\S_{20}=523.5602~\text{mg}$

Greatest amount of antibiotic present = 523.5602 mg

This amount is almost constant after 3rd dose, so it will occur after every dose after 3rd dose

<h3>Drug present in body at different points:</h3>

After 1st dose = 500mg

After 2nd dose = 522,5mg

After 3rd dose = 523.513 mg

After the the amount left in the body almost remains constant.

Which means that after each dose, the amount in body is maximum, at the end of the 12 hours, the amount reduces to 4.5%, which reaches almost the same maximum after taking another dose.

5 0

3 years ago

What is the answer or how do I solve this

mojhsa [17]

Answer:

x=21

<EAF=52°

<EAL=104°

Step-by-step explanation:

Since it has a bisector, the two angles are equal.

2x+10=3x-11

10+11=3x-21